Answer:
see explanation
Step-by-step explanation:
a
The tangent and the radius at the point of contact form a right angle
Using Pythagoras' identity on the right triangle formed.
Let x be the distance from the centre to P, then
x² = 4² + 10² = 16 + 100 = 116 ( take the square root of both sides )
x = ≈ 10.77 cm (to 2 dec. places )
b
let the required angle be Θ, then
Using the sine or cosine ratio in the right triangle.
cosΘ = =
Θ = (
) ≈ 21.8°
Answer:
(a)
Distance from player should be 13.82 feet or 36.2 feet
(b)
The ball will go over the net
Step-by-step explanation:
we are given
The ball follows a path given by the equation
where
x and y are measured in feet and the origin is on the court directly below where the player hits the ball
(a)
net height is 8 ft
so, we can set y=8
and then we can solve for x
we can use quadratic formula
So, distance from player should be 13.82 feet or 36.2 feet
(b)
we can plug x=30 and check whether y=8 ft
we know that
height of net is 8 ft
so, the ball will go over the net