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Nikitich [7]
3 years ago
8

Which is equivalent to 15(-3 5/8)

Mathematics
1 answer:
marysya [2.9K]3 years ago
8 0
15(-3 5/8). 15( -29/8). 15 x -29/8. = -435/8. Answer = - 435/8
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This statement accurately describes how to determine the Y intercept and the slope from the graph below
Artist 52 [7]

Answer:

i dont see nun

Step-by-step explanation:

please explain

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2 years ago
I NEED HELP WITH THIS ASAP!!
brilliants [131]

Answer:

125 degrees

Step-by-step explanation:

Since they are alternate exterior angles, the angles are equal, therefore leaving you with 125 degrees.

7 0
3 years ago
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a DLT earns $14 an hour when she works days and $18 an hour when she works nights. One month shr works six 4 hour days, 3 eight
mina [271]
I think the answer is $1,092?
3 0
3 years ago
Xy′ = √(1 − y2 ), y(1) = 0
Ulleksa [173]

Answer:

The particular solution is y=\sin (\ln|x|) .

Step-by-step explanation:

The given differential equation is

xy'=\sqrt {1-y^2}

It can be written as

x\frac{dy}{dx}=\sqrt {1-y^2}

Use variable separable method to solve the above equation.

\frac{dy}{\sqrt {1-y^2}}=\frac{1}{x}dx

Integrate both sides.

\int \frac{dy}{\sqrt {1-y^2}}=\int \frac{1}{x}dx

\sin^{-1} y=\ln|x|+C            .... (1)

It is given that y(1)=0. It means y=0 at x=1.

\sin (0)=\ln|1|+C

0=0+C

0=C

The value of constant is 0.

Substitute C=0 in equation (1) to find The required equation.

\sin^{-1} y=\ln|x|+0

Taking sin both sides.

y=\sin (\ln|x|)

Therefore the particular solution is y=\sin (\ln|x|) .

7 0
3 years ago
Ya'll fr get 50 points if you answer this. <br> What is the rate of change of <img src="https://tex.z-dn.net/?f=f%28x%29%3D2%5Ex
Evgesh-ka [11]

Answer:

\dfrac{dy}{dx}=2^x\ln 2

Step-by-step explanation:

**This is a non-linear function and therefore <u>does not have a constant rate of change</u>.  It will have a different slope depending on what points you use in the average rate of change formula:\mathsf{average \ rate \ of \ change = \dfrac{change \ in \ y}{change \ in \ x}}

To calculate rate of change, differentiate.

substitute y for f(x):  

\implies y=2^x

Take natural logs of both sides:

\implies \ln y=\ln 2^x

Apply the log rule  \ln a^b=b \ln a :

\implies \ln y=x\ln 2

Differentiate with respect to x:

\implies \dfrac{1}{y} \frac{dy}{dx}=\ln 2

Mulitply both sides by y:

\implies \dfrac{dy}{dx}=y\ln 2

Replace y with y=2^x

\implies \dfrac{dy}{dx}=2^x\ln 2

Therefore, rate of change of the function is :

\dfrac{dy}{dx}=2^x\ln 2

8 0
2 years ago
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