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3 years ago

8

Which is equivalent to 15(-3 5/8)

1 answer:

marysya [2.9K]3 years ago

8 0

15(-3 5/8). 15( -29/8). 15 x -29/8. = -435/8. Answer = - 435/8

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This statement accurately describes how to determine the Y intercept and the slope from the graph below

Artist 52 [7]

Answer:

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Step-by-step explanation:

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2 years ago

I NEED HELP WITH THIS ASAP!!

brilliants [131]

Answer:

125 degrees

Step-by-step explanation:

Since they are alternate exterior angles, the angles are equal, therefore leaving you with 125 degrees.

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3 years ago

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a DLT earns $14 an hour when she works days and $18 an hour when she works nights. One month shr works six 4 hour days, 3 eight

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I think the answer is $1,092?

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3 years ago

Xy′ = √(1 − y2 ), y(1) = 0

Ulleksa [173]

Answer:

The particular solution is $y=\sin (\ln|x|)$ .

Step-by-step explanation:

The given differential equation is

$xy'=\sqrt {1-y^2}$

It can be written as

$x\frac{dy}{dx}=\sqrt {1-y^2}$

Use variable separable method to solve the above equation.

$\frac{dy}{\sqrt {1-y^2}}=\frac{1}{x}dx$

Integrate both sides.

$\int \frac{dy}{\sqrt {1-y^2}}=\int \frac{1}{x}dx$

$\sin^{-1} y=\ln|x|+C$ .... (1)

It is given that y(1)=0. It means y=0 at x=1.

$\sin (0)=\ln|1|+C$

$0=0+C$

$0=C$

The value of constant is 0.

Substitute C=0 in equation (1) to find The required equation.

$\sin^{-1} y=\ln|x|+0$

Taking sin both sides.

$y=\sin (\ln|x|)$

Therefore the particular solution is $y=\sin (\ln|x|)$ .

7 0

3 years ago

Ya'll fr get 50 points if you answer this. <br> What is the rate of change of <img src="https://tex.z-dn.net/?f=f%28x%29%3D2%5Ex

Evgesh-ka [11]

Answer:

$\dfrac{dy}{dx}=2^x\ln 2$

Step-by-step explanation:

**This is a non-linear function and therefore <u>does not have a constant rate of change</u>. It will have a different slope depending on what points you use in the average rate of change formula: $\mathsf{average \ rate \ of \ change = \dfrac{change \ in \ y}{change \ in \ x}}$

To calculate rate of change, differentiate.

substitute y for $f(x)$ :

$\implies y=2^x$

Take natural logs of both sides:

$\implies \ln y=\ln 2^x$

Apply the log rule $\ln a^b=b \ln a$ :

$\implies \ln y=x\ln 2$

Differentiate with respect to $x$ :

$\implies \dfrac{1}{y} \frac{dy}{dx}=\ln 2$

Mulitply both sides by $y$ :

$\implies \dfrac{dy}{dx}=y\ln 2$

Replace $y$ with $y=2^x$

$\implies \dfrac{dy}{dx}=2^x\ln 2$

Therefore, rate of change of the function is :

$\dfrac{dy}{dx}=2^x\ln 2$

8 0

2 years ago