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Elanso [62]
2 years ago
10

Describe the end behavior of f(x)=2x^3

Mathematics
1 answer:
monitta2 years ago
4 0

Answer:

as x→+∞, f(x)→+∞   as x→-∞,f(x)→-∞

Step-by-step explanation:

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20 points!!! Solve Each Proportion-Round to the nearest tenth *<br> Your answer
KatRina [158]

Answer:

x = 3.6

B. {7.88}

Step-by-step explanation:

\frac{6}{x}= \frac{10}{6}

x · 10 = 6 · 6

10x = 36

10x ÷ 10 = 36 ÷ 10

x = 3.6

\frac{9}{8} =\frac{x}{7}

8 · x = 9 · 7

8x = 63

8x ÷ 8 = 63 ÷ 8

x=7\frac{7}{8} or x = 7.875

7.875 rounded to the nearest tenth is 7.88.

8 0
2 years ago
A ____ is written as an if-then statement A.conjecture B.counterexample C.conditional D.negation​
Kaylis [27]

Answer:

D

Step-by-step explanation:

I think D is the answer.

5 0
3 years ago
Read 2 more answers
On the 40th birthday, Mr. Ramos decided to buy a pension plan for himself. This plan will allow him to claim
Mama L [17]

Answer:

The amount of one-time payment should he make on his 40th birthday to pay off his pension plan is P32,880.77.

Step-by-step explanation:

Step 1: Calculation of present value on 3 months after his 60th birthday

The present value on 3 months after his 60th birthday can be calculated using the formula for calculating the present value of an ordinary annuity as follows:

PV60 = Q * ((1 - (1 / (1 + r))^n) / r) …………………………………. (1)

Where;

PV60 = present value on 3 months after his 60th birthday = ?

Q = quarterly claim = P10,000

r = quarterly interest rate = annual interest rate / 4 = 8% / 4 = 0.08 / 4 = 0.02

n = number of quarters = number of years * Number of quarters in a year = 5 * 4 = 20

Substitute the values into equation (1), we have:

PV60 =  P10,000 * ((1 - (1 / (1 + 0.02))^20) / 0.02)

PV60 = P10,000 * 16.3514333445971

PV60 = P163,514.33  

Step 2: Calculation of one-time payment on his 40th birthday

The one-time payment can be calculated using the formula the following formula:

PV = PV60 / (1 + r)^n ........................ (2)

Where;

PV = Present value or One-time payment = ?

PV60 = present value on 3 months after his 60th birthday = P163,514.33

r = quarterly interest rate = annual interest rate / 4 = 8% / 4 = 0.08 / 4 = 0.02

n = number of quarters from 40th to 3 months after his 60th birthday = (number of years * Number of quarters in a year) + One quarter = (20 * 4) + 1 = 81

Substitute the values into equation (2), we have:

PV = P163,514.33 / (1 + 0.02)^81 = P32,880.77

Therefore, the amount of one-time payment should he make on his 40th birthday to pay off his pension plan is P32,880.77.

7 0
3 years ago
Emma recently purchased a new car she decided to keep track of how many gallons of gas they used on five other business trips th
spayn [35]
Emma recently purchased a new car. She k business trips. The results are shown in the table below. decided to keep track of how many gallons of gas she used on five of her 1. Number of Miles Driven Gallons Used 150 200 400 600 1000 10 19 29 51 Write the linear regression equation for these data where miles driven is the independent variable. (Round all values to the nearest hundredth.) 2. The table below shows the number of grams of earbohydrates, x, and the number of Calories, y, of six different foods. Carbohydrates () Calories () 120 138 147 9.5 10 6 108 62 Which equation best represents the line of best fit for this set of data? 1) У-15х У-0.17-04 y-14.1x+5.8 3) 4) 2) у" 0.07x ow shows the median diameter of grains of sand and the slope of the beach for 9 naturally occurring ocean beaches. Median Diameter of 0.17 0.19 0.22 0.235 0.235 0.3 0.3 0.35 0.42 0.85 Grains of Sand in Millimeters (3) Slope of Beach 0.63 in Degrees (y) 0.7 0.82088 1 1.15 1.54.4 7.3 11.3 Write the linear regression equation for this set of data, ro at a degree, on a Using this equation, predict the slope of a beach, to the nearest tenth of a degree median diameter of 0.65 mm. on a beach with grains of sand having a
6 0
2 years ago
You have a 1200-foot roll of fencing and a large field. you want to make two paddocks by splitting a rectangular enclosure in ha
romanna [79]
Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change  w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
8 0
3 years ago
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