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Elden [556K]
3 years ago
9

I miss the equation, point D.

Mathematics
1 answer:
Maru [420]3 years ago
7 0
The answer is : Sn = S(n-1) + n
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What is the solution of x+8/5x-1>0?
DerKrebs [107]

Answer:

x<-8 or x>1/5

Step-by-step explanation:

\frac{x+8}{5x-1} >0

First we replace > symbol by = sign

\frac{x+8}{5x-1} =0

To solve for x we multiply 5x-1 on both sides

x+8 =0

x=-8

5x-1=0 solve for x

x= 1/5

WE got two values x=-8  and x= 1/5

Now we make a number line and check with each interval

x<-8,  -8<x<1/5,  x>1/5

Pick x= -9 and check with the given inequality

\frac{-9+8}{5(-9)-1} >0

1/46 >0 is true, so x<-8 satisfies our inequality

Pick x= 0 and check with the given inequality

\frac{0+8}{5(0)-1} >0

-8 >0 is false , -8<x<1/5 does not satifies our inequality

Pick x= 2 and check with the given inequality

\frac{2+8}{5(2)-1} >0

10/9>0 is true , x>1/5  satisfies our inequality

3 0
3 years ago
Read 2 more answers
Is this a function please help I’m failing
igomit [66]

Answer:

Yes

Step-by-step explanation:

The relation is a function. For a relation to be a function there must be a unique x value for each y value. So this means x's can not repeat, and in this relation, the x-values never repeat. Therefore this is a function.

7 0
3 years ago
(x,-4) and (2,8): m = -3 find the missing value. it is in slope formula.
Snezhnost [94]

Answer:

The value of x = 6

Step-by-step explanation:

Given

  • The point (x,-4)
  • The point (2,8)

To determine

  • m = -3

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

here:

  • (x₁, y₁) = (x, -4)
  • (x₂, y₂) = (2, 8)
  • m = -3

so substitute (x₁, y₁) = (x, -4) , (x₂, y₂) = (2, 8)  and m = -3

m =  [y₂ - y₁] /  [x₂ - x₁]

-3 =  [8 - (-4)] / [2 - x]

-3 = [12] / [2-x]  

-3 (2-x) = 12

-6+3x = 12

3x = 12+6

3x = 18

divide  both sides by 3

3x/3 = 18/3

x = 6

Therefore, the value of x = 6

7 0
3 years ago
2(x+3)^2+2(y)^2=32 what is the center point of the circle and how long is the radius
spayn [35]

Answer:

  • center (-3, 0)
  • radius 4

Step-by-step explanation:

The standard form equation of a circle is ...

  (x -h)^2 +(y -k)^2 = r^2 . . . . . . . . . center at (h, k), radius r

Divide your given equation by 2 to put it into standard form:

  (x +3)^2 +y^2 = 16

Comparing to the above, we see ...

  • h = -3
  • k = 0
  • r = √16 = 4

The center point of the circle is (-3, 0); the radius is 4 units long.

6 0
3 years ago
I will mark you brainliest!!! Identify the type of function.
Ymorist [56]

Answer:

quadratic

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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