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2 years ago

Find the radius of the circle with the given diameter. 1. 10 inches

Mathematics

1 answer:

Vlad [161]2 years ago

4 0

Answer:

5 inches

Step-by-step explanation:

the diameter is just Rx2 (R being the radius)

and the radius is D divided by 2 (D is the diameter)

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What is the vertex of the quadratic function f(x) = (x – 8)(x – 2)?<br><br> (<br> ,<br> )

irakobra [83]

Answer:

⅞2781x 3862

Step-by-step explanation:

i don't know but that is my answer ok kayat taposin Mona ang module mo

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3 years ago

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Find the given term 11, -33,99 9th term

kvv77 [185]

Assuming the sequence goes on like this 11,-33,99,-297,891,...,
its general formula is $a_n=-11\cdot(-1)^n\cdot3^{n-1}$

So, the 9th term is
$a_9=-11\cdot(-1)^9\cdot3^{9-1}=-11\cdot(-1)\cdot6561=72171$

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2 years ago

Two triangles are similar, and the ratio of the corresponding sides is 1:5, and which of the following is true?

IrinaK [193]

Answer:

Step-by-step explanation:

7 0

3 years ago

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George says that 4+ a +a+a+b+b=24ab

antoniya [11.8K]

Answer:

3a+2b+4

Step-by-step explanation:

24ab indicates that there is 24 of unit ab which there is not. there is 4+ 3a+2b

4 0

2 years ago

The table shows a company’s profit based on the number of pounds of food produced.

Bingel [31]

Answer:

$5,300

Step-by-step explanation:

Formulae used,

$a=\dfrac{(\sum x^2y\sum xx)-(\sum xy\sum xx^2)}{(\sum xx\sum x^2x^2)-({\sum xx^2)}^2}$

$b=\dfrac{(\sum xy\sum x^2x^2)-(\sum x^2y\sum xx^2)}{(\sum xx\sum x^2x^2)-({\sum xx^2)}^2}$

$c=\dfrac{\sum y}{n}-b\frac{\sum x}{n}-a\frac{\sum x^2}{n}$

Where,

$\sum xx=\sum x^2-\dfrac{(\sum x)^2}{n}$

$\sum xy=\sum xy-\dfrac{\sum x\sum y}{n}$

$\sum xx^2=\sum x^3-\dfrac{\sum x\sum x^2}{n}$

$\sum x^2y=\sum x^2y-\dfrac{\sum x^2\sum y}{n}$

$\sum x^2x^2=\sum x^4-\dfrac{(\sum x^2)^2}{n}$

Putting the values from the table, we get the best fit line as,

$y= -0.0817x^2 + 102.24x - 20421$

As we want to calculate the profit at 350 pounds, so putting x=350, we get

$y= -0.0817(350)^2 + 102.24(350) - 20421=\$5354.75$

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3 years ago

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