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klio [65]
2 years ago
10

Can choose two answers!

Mathematics
1 answer:
MissTica2 years ago
5 0
The answer is 1th and 2 nd
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Which statement describes the inverse of m(x) = x^2 – 17x?
DochEvi [55]

Given:

The function is

m(x)=x^2-17x

To find:

The inverse of the given function.

Solution:

We have,

m(x)=x^2-17x

Substitute m(x)=y.

y=x^2-17x

Interchange x and y.

x=y^2-17y

Add square of half of coefficient of y , i.e., \left(\dfrac{-17}{2}\right)^2 on both sides,

x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2        [\because (a-b)^2=a^2-2ab+b^2]

Taking square root on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}

Add \dfrac{17}{2} on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y

Substitute y=m^{-1}(x).

m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}

We know that, negative term inside the root is not real number. So,

x+\left(\dfrac{17}{2}\right)^2\geq 0

x\geq -\left(\dfrac{17}{2}\right)^2

Therefore, the restricted domain is x\geq -\left(\dfrac{17}{2}\right)^2 and the inverse function is m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}.

Hence, option D is correct.

Note: In all the options square of \dfrac{17}{2} is missing in restricted domain.

7 0
3 years ago
One sixth of fifty four
marissa [1.9K]
1/6 x 54 = 9
Hope this helps ;)
8 0
2 years ago
When The sum of 1. 3240 and 1. 4872 is subtracted from 4. 0121 it will give you the difference of
Paladinen [302]

Answer:

C. 1.2009

Step-by-step explanation:

1.3240 + 1.4872 = 2.8112

4.0121 - 2.8112 = 1.2009 - C

8 0
3 years ago
Which of the following is a solution of y - x &lt; -3?<br><br> (6, 2)<br> (2, 6)<br> (2, -1)
Snowcat [4.5K]
Personally I'd solve this inequality for y first:  y < x-3.

That immediately eliminates (6,2) and (2,6).

Starting from y < x-3 and letting 2 sub for x and -1 sub for y, is the following true or false?

-1 < 2 -3     NO.  -1 < -1 is false.  Was there a fourth answer choice?

5 0
3 years ago
Read 2 more answers
How do I find out if a function is in standard form
anzhelika [568]
Hey!

A function in slope-intercept form would look like y=mx+b; with the x and y values on the opposites of the equation.

A function in standard form would look like ax+by=c; with the x and y values on the same side of the equation.


Hope this helps!

3 0
3 years ago
Read 2 more answers
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