As a single logarithm, 2log2 6- log29+ 1/3log2 27 = log2 12.
1 answer:
Answer:
true
Step-by-step explanation:
2log2 6- log2 9+ 1/3log2 27 =
= log2 6² - log2 9 + log2 27^(1/3)
= log2 36 - log2 9 + log2 3
= log2 [(36 × 3)/9]
= log2 12
The statement is true.
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