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Allushta [10]
2 years ago
13

Brianna brought 15 cookies to class for her and her friend. Brianna’s friend ate twice the amount of cookies as Brianna. Brianna

ate 4 cookies. How many cookies are left over? Write an equation.
Mathematics
2 answers:
Norma-Jean [14]2 years ago
4 0

Answer:

3 cookies

Step-by-step explanation:

If briannas freind ate twice than her then her freind ate 8 and add 4 and 8 and get 12, the subtract 12 from 15 and 15-12 is 3 so she has 3 cookies

geniusboy [140]2 years ago
3 0

Answer:

8

Step-by-step explanation:

  30 divided by 4 ,7.5 then round its 8

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Spinner 1 is divided into four congruent sections, and Spinner 2 is divided into three congruent sections, as shown below. Each
xenn [34]

Answer:

I believe the answer would be 1/6

Step-by-step explanation:

The work already says that there are 2 possible choices. This would be 2/12. This is further simplified to 1/6. Hope this helps

3 0
3 years ago
Read 2 more answers
Find (g • f) ^(3) PLEASE HELLPP
spayn [35]
The first thing we are going to do to find (g°f)(3), is find (g°f)(x). To do that, we are going to evaluate g(x) at f(x):
(g°f)(x)=g(f(x))=g(3x-2)=(3x-2)^2=9x^2-12x+4

Now, we can evaluate (g°f) at 3:
g(f(3))=9(3)^2-12(3)+4
g(f(3))=9(9)-36+4
g(f(3))=81-32
g(f(3))=49

We can conclude that the correct answer is c. 49
6 0
3 years ago
Factor using x method and foil to prove
Olegator [25]
Answer:
Step by step:
8 0
3 years ago
Which of the following are true statements.
Mariulka [41]

Answer:

Second statement is true.

The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

Step-by-step explanation:

for first part of statement

The lengths 7, 40 and 41 can not be sides of a right triangle.

If the square of long side is equal to the sum of square of other two sides

then the given length can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

c^{2} =a^{2} +b^{2}----------(1)

Let c=41 and a = 7 and b=40

Put all the value in equation 1.

41^{2} =7^{2} +40^{2}

1681=49+1600

1681=1649

Therefore, the square of long side is not equal to the sum of square of other two sides, So given lengths 7, 40 and 41 can not be sides of a right triangle.

for second part of statement.

The lengths 12, 16, and 20 can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

Let c=20 and a = 12 and b=16

20^{2} =12^{2} +16^{2}

400=144+256

400=400

Therefore, the square of long side is equal to the sum of square of other two sides, So given the lengths 12, 16, and 20 can be sides of a right triangle.

Therefore, The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

8 0
3 years ago
The fuel cost per hour for running a ship is approximately one half the cube of the speed (measured in knots) plus additional fi
andrezito [222]

Answer:

6 knots

Step-by-step explanation:

Let the speed be v knots

then time taken to cover 500 M = 500 / v hrs

fuel consumption /hr = 216 + 0.5v^3

let F be the fuel consumption for trip

= [500/v][216 + 0.5v^3]

= 500[216/v + 0.5v^2]

dF/dv = 500[ - 216/v^2 + v]

d^2F/d^2v = 500[432/v^3 + 1] , i.e. +ve

so setting dF/dv will give a minima

500[ -216/v^2 + v] = 0

or v = 216/v^2

or v^3 = 216

solving, we get v = [216]^(1/3) = 6 knots

7 0
3 years ago
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