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3 years ago

Marge is twice as old as Consuelo. The sum of their ages seven years ago was 13. How old are they now?

Mathematics

2 answers:

Trava [24]3 years ago

7 0

Merge is 18.
Conseulo is 9

LiRa [457]3 years ago

4 0

Marge is 18 and Consuelo is 9

This is because you can add 14 to the sum of their ages 7yrs ago to find out the sum of their ages now. This is 27.
18 + 9 = 27 (9 x 2 = 18) (this is now)
And to double check : (7yrs ago)
18 - 7 = 11 9 - 7 = 2
11 + 2 = 13

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Combine the like terms to create an equivalent expression 10k + 4k

ludmilkaskok [199]

Answer:

14k

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3 years ago

Show work for an opportunity to receive partial credit. Find the value of x.<br> 12 = - 4-6x-3)

masya89 [10]

Answer:

I will gladly let you have partial credit! I am putting two different ones because I am not sure why the parenthesis is at the end. Just pick whichever one looks like the question you have. Hope this helps!

Step-by-step explanation:

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3 years ago

The table below represents a linear function f(x) and the equation represents a function g(x):

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Answer:

<u>Use 2 points from he table to find the slope of f(x):</u>

(0, -1) and (1, 7)

<u>The slope is:</u>

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f(x) = 8x - 1
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3 years ago

Solve the polynomial equation

ExtremeBDS [4]

Hey there!

You can solve this by squaring both sides to first cancel out the square root on the left. Then, you can eliminate each term as your normally would.

$2 \sqrt{x} =x-3$

$(2 \sqrt{x})^{2} = (x-3)^{2}$

$(4x) = (x-3)(x-3)$

$4x = x^{2} -6x+9$

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Now, you're given the opportunity to find your solution using the quadratic formula. That formula is:

$\frac{-b_-^+ \sqrt{b^2-4ac} }{2a}$

You can find out a, b, and c by comparing your new equation to the standard form. Luckily, we just put our equation into standard form:

$ax^{2} + bx + c$

$x^{2} -10x+9$

$a = 1 \\ b = -10 \\ c = 9$

To find your solution, plug these numbers into the quadratic formula and solve.

$\frac{-b_-^+ \sqrt{b^2-4ac} }{2a}$

$\frac{10_-^+ \sqrt{-10^2-4(9)}}{2}$

Remember to use PEMDAS when solving these problems.

$\frac{10_-^+ \sqrt{100-36}}{2}$

$\frac{10_-^+ \sqrt{64}}{2}$

$\frac{10_-^+ 8}{2}$

Now, solve this final bit by adding the top terms then subtracting them for two different answers.

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Don't assume that both of these are correct. The very last step is to plug both of these into the original problem you were given and see if they make the equation true.

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Hope this helped you out! :-)

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3 years ago

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AveGali [126]

Hey There!

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</span>
Hope this helps :)

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3 years ago