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2 years ago

HELP PLEASE GIVING AWAY 30 POINTS

Mathematics

2 answers:

insens350 [35]2 years ago

5 0

Answer:

48 inches

Step-by-step explanation:

the guy a bouve me is right

Step2247 [10]2 years ago

3 0

Answer:

48 inches.

Step-by-step explanation:

The triangle is an isoscele triangle.

An isosceles triangle is a triangle with two sides of the same length.

h is opposite of the other side of 48 inches and judging by the picture, it looks exactly the same, therefore the answer is 48 inches.

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If B is the midpoint of AC and AB = 4x + 14 and BC = x + 20, determine how long AC is.

Serhud [2]

Answer:

44 units

Step-by-step explanation:

Since B is the mid-point of AC

AB=BC

or,4x+14=x+20

or, 4x-x=20-14

or 3x=6

or,x=6/3=2

AC=AB+BC

= 4x+14+x+20

= 4(2) + 14 +2 +20

= 8+14+22

=44 units

5 0

3 years ago

Read 2 more answers

180 ° 35 ° X ° X = ? °

just olya [345]

Answer:

x=145°

Step-by-step explanation:

180 = 35 + x

x = 180-35

x= 145°

3 0

3 years ago

You are selling lemonade for $1.50, a bag of kettle corn for $3, and a hot dog for $2.50 at a fair. Write and simplify an expres

kozerog [31]

Answer:

1.5p + 3p + 2.5p

Step-by-step explanation:

This expression, 1.5p + 3p + 2.5p, will represent the amount of money received when p people buy one of each food item.

Since the price of each is the coefficient for p, this will represent how much money will be gained from each food item. All 3 terms will be added together to represent the total amount of money gained from selling all 3 items.

4 0

3 years ago

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

3 0

3 years ago

2 x - 17 = 11. Help please

Svet_ta [14]

Step-by-step explanation:

Perhaps you want to solve the equation for the value of x. If so then let us work it out:

$2x - 17 = 11 \\ 2x = 11 + 17 \\ 2x = 28 \\ x = \frac{28}{2} \\ \huge \red { \boxed{x = 14}}$

8 0

3 years ago