Answer:
see below
Step-by-step explanation:
4 ^(3x-1)=3
Take the natural log of each side
ln(4 ^(3x-1))= ln (3)
We know that ln ( a^b) = b ln a
(3x-1) ln 4 = ln 3
Divide each side by ln 4
3x-1 = ln(3)/ (ln4)
Add 1 to each side
3x = ln(3)/ ln (4) +1
Divide by 3
x =1/3 [( ln 3)/ ln (4)] + 1/3
x = .792461
X/49 = 21/x
x^2 = 21(49) = 1029
x = √1029 = 32.1
x = 32.1
Answer:
x = 15 units
Step-by-step explanation:
Here, base of triangle = x units & height = 19 units

Answer is 3 seconds
When the bullet reaches the ground, ground being x in graph (and here its s which is = 0)
s = -16t^2 + 48t
s = 0, solve for t
0 = -16t^2 + 48t
0 = t ( -16t + 48)
0 = 16t ( - t + 3)
now you have two equation
0 = 16t and 0 = -t +3 ( you can look at the graph line touches x twice)
0 = 16 t
0 = t ( you know its false, because time = 0)
You are left with
0 = -t + 3
t = 3
It takes 3 seconds for the bullet to return to the ground.
// Hope this helps.
Solve. To solve this equation, you must change the divide sign into a multiplication sign.
To do so, change it into a multiplication sign, and flip the second fraction
(5/12)/(2/11) = 5/12 x 11/2
Multiply across
5/12 x 11/2 = 55/24
55/24, or 4 7/12
hope this helps
<em>~Rise Above the Ordinary</em>