Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan
= 5/11.65
=23.23°
AC=
km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
The answer is 6, reaosn is because 6/8 is not simplified, so if we divide both sides by 2 (the numerator and the denominator), we can get a simplified fraction, which is 3/4. Steps: 6/8, 6 divided by 2/8 divided by 2, 3/4.
Hope this helped!
Nate
1.5 is lesser than 0.5. Oh, wait nevermind I meant to say -1.5 is lesser than 0.5
Feet
_____
second
10 feet
________
16 second
equals
.625 feet per second
Answer:
no, because it has a constant rate of change
Step-by-step explanation:
this is because the x and y change at the same rate. non linear means that they dont change at the same rate.