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2 years ago

WILL MARK BRAINLIEST The amount (A) that principal (P) will be worth after t years at interest rate (r) compounded annually is

Mathematics

1 answer:

alex41 [277]2 years ago

4 0

Answer:

15 years

Step-by-step explanation:

Since we're looking for time, we can use the formula t = A / Pr, which would be:
t = 6000/(7255 x 5.5%)
Converting the percentage into decimal form
t = 6000/(7255 x 0.055)
We can then solve to get:
t = 6000/399.025
t = 15.03665183...
Meaning it would take 15 years for an interest of 5.5% on $6,000 to reach $7,255. Not very worth $1,255 extra if you need that 6k for rent.

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A zookeeper is monitoring the population of gazelles. The herd needs three times more males than females to thrive, and the zoo

avanturin [10]

Answer:

0 < x ≤ 12 and 0 < y ≤ 36

Step-by-step explanation:

Here, x represents the number of female gazelles and y represents the number of male gazelles.

The zoo only has room for 12 female gazelles.

∵ The number of rooms must be more than or equal to the total female gazelles ,

12 ≥ x

Also, number of animals can not be negative,

And, it must be greater than 0.

⇒ 0 < x ≤ 12,

⇒ 3(0) < 3x ≤ 3(12)

⇒ 0 < 3x ≤ 36

∵ Number of males gazelles = 3 × number of female gazelles

⇒ y = 3x

⇒ 0 < y ≤ 36

Hence, the constraints to represent a thriving population of gazelles at the zoo are,

0 < x ≤ 12,

0 < y ≤ 36

7 0

2 years ago

Read 2 more answers

How do i figure this out?

julsineya [31]

Answer:

Step-by-step explanation:

put the left hand numbers into your calculator, find the answers.

put the equations at the bottom in your calculator and figure out which is equal to which

1. fourth answer on the botton

2. first one

3. third one

4. second one

4 0

2 years ago

7. In 2015 a club has 250 members who each

Evgen [1.6K]

2015:

250 members

$95 annual subscription

2016

250 members + 4%

$95 annual subscription + 6%

Work:

250 x 1.04 = 260

95 x 1.06 = 100.7

260 x 100.7 = 26,182

Thus, the club makes $26,182 from 260 members who pay a subscription of $100.7

3 0

3 years ago

in the product rule for exponents, what do you do to the coefficients? what do you do to the exponents?

docker41 [41]

Answer:

Do not multiply the coefficients and the exponents. Remember, using the Product Rule add the exponents when the bases are the same.

5 0

3 years ago

Read 2 more answers

Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es

Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4× $(1/2)^{\infty}$

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

$S_{\infty} = \dfrac{a}{1 - r}$

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

$La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty} = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2$

La suma al infinito de las áreas de los cuadrados, $S_{\infty}$ = 8 in.²

7 0

2 years ago