I'm not sure how you got c but the way you would solve this is for every x on the line plot you would add that amount. You don't need to worry about 0 because 0 is nothing.
There are 3 X's at 1/4 so you would add 1/4+1/4+1/4=3/4. There are 2 X's at 1/2 so you would add 1/2+1/2=1. There are 2 X's at 3/4 so you would add 3/4+3/4=1.5. There is 1 X at 1 so it would just be 1. Then add all those together 3/4+1+1.5+1=4.25 or you could just add each X as you come across it on the number line like so:
1,503 + 847 + 4,219 = 6,569
Answer:
The vertices are (-16,-5) and (14,-5)
The foci are (-26,-5) and (24,-5)
Please, see the attached file.
Thanks.
Solution:
<u>We know that:</u>
![Area \ of \ triangle = \dfrac{1}{2} \times Base \times Height](https://tex.z-dn.net/?f=Area%20%5C%20of%20%5C%20triangle%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%20%5Ctimes%20Base%20%5Ctimes%20Height)
<em>Since we are already given the base and the height, we can substitute them into the formula to find the area of the triangle.</em>
![Area \ of \ triangle = \dfrac{1}{2} \times 18 \times24](https://tex.z-dn.net/?f=Area%20%5C%20of%20%5C%20triangle%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%20%5Ctimes%2018%20%5Ctimes24)
<u>Cancel out the "2" by dividing it by 18.</u>
![Area \ of \ triangle = 9 \times24](https://tex.z-dn.net/?f=Area%20%5C%20of%20%5C%20triangle%20%3D%20%209%20%5Ctimes24)
<u>Simplify the multiplication.</u>
![\bold{Area \ of \ triangle = 216 \ ft^{2}}](https://tex.z-dn.net/?f=%5Cbold%7BArea%20%5C%20of%20%5C%20triangle%20%3D%20%20216%20%5C%20ft%5E%7B2%7D%7D)
<span>f(x) = 1.5 x (1 - x)
f(0.8) = 1.5(0.8)(1 - 0.8) = 0.24
f(0.24) = 1.5(0.24)(1 - 0.24) ~= 0.274
f(0.274) = 1.5(0.274)(1 - 0.274) ~= 0.298
f(0.298) = 1.5(0.298)(1 - 0.298) ~= 0.314
f(0.314) = 1.5(0.314)(1 - 0.314) ~= 0.323
</span>So the answer is D : 0.24, 0.274, 0.298, 0.314, 0.323