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NemiM [27]
3 years ago
12

What is the length of PR ? A. 23π B. 83π C. 43π D. 163π

Mathematics
1 answer:
slava [35]3 years ago
3 0
I believe it’s 2/3pi radians.
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We want to find the maximum and minimum values of f(x, y) = 10x2 + 11y on the disk D: x2 + y2 < 1.
dolphi86 [110]

If you're just focusing on the boundary, it's the circle x^2+y^2=1. Parameterize it by taking x=\cos t and y=\sin t, with 0\le t\le2\pi. Then f(x,y) reduces to a univariate function g(t):

f(x,y)=10x^2+11y\iff g(t)=f(\cos t,\sin t)=10\cos^2t+11\sin t

Then you can find any extrema on the boundary by checking the critical points of g.

8 0
4 years ago
Quadrilateral ABCD is a rectangle. If AG = -7j + 7 and DG = 5j + 43, find BD
Kaylis [27]

<em>BD</em> = 56

Step-by-step explanation:

Step 1: In rectangle, the diagonals are congruent and bisect each other.

So, <em>AC</em> = <em>BD</em>

⇒<em>AG</em> + <em>GC</em> = <em>BG</em> + <em>GD</em>

⇒<em>AG</em> + <em>AG</em> = <em>GD</em> + <em>GD</em>

⇒ 2<em>AG</em> = 2<em>GD</em>

⇒<em>AG</em> = <em>GD</em>

⇒ –7<em>j </em>+ 7 = 5<em>j</em> + 43

⇒–7<em>j</em> – 5<em>j</em> = 43 – 7

⇒–12<em>j</em> = 36

⇒<em>j</em> = –3

Step 2: <em>BD</em> = 2<em>DG</em>

<em>BD</em> = 2(5<em>j</em> + 43)

     = 2(5 (–3) + 43)

     = 2(–15 + 43)

     = 2 × 28

     = 56

Hence, <em>BD</em> = 56.

4 0
3 years ago
Question 8 options:
shusha [124]

Answer:

volume of cone=1/3 πr²h=1/3 ×π×5²×15=125πcm³

4 0
3 years ago
What is the fourth term in the binomial expansion (a+b)^6)
Dafna11 [192]

Answer:

20a^3b^3

Step-by-step explanation:

<u>Binomial Series</u>

(a+b)^n=a^n+\dfrac{n!}{1!(n-1)!}a^{n-1}b+\dfrac{n!}{2!(n-2)!}a^{n-2}b^2+...+\dfrac{n!}{r!(n-r)!}a^{n-r}b^r+...+b^n

<u>Factorial</u> is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.

Example:  4! = 4 × 3 × 2 × 1

Therefore, the fourth term in the binomial expansion (a + b)⁶ is:

\implies \dfrac{n!}{3!(n-3)!}a^{n-3}b^3

\implies \dfrac{6!}{3!(6-3)!}a^{6-3}b^3

\implies \dfrac{6!}{3!3!}a^{3}b^3

\implies \left(\dfrac{6 \times 5 \times 4 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}{3 \times 2 \times 1 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}\right)a^{3}b^3

\implies \left(\dfrac{120}{6}\right)a^{3}b^3

\implies 20a^3b^3

7 0
2 years ago
Please help <br> And do step by step plz and thank you
Law Incorporation [45]

Answer:

Each child gets 3/2 cookies

Step-by-step explanation:

3/2=1.5 therefore they both get 1.5 or 1 and a half cookies each. 1.5= 3/2

Hope you find this helpful. I am happy to help you whenever I can.

3 0
3 years ago
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