Find the equation of the straight line with the gradient -2/3 and passing through the point(1,1)

1 answer:

4 0

Answer:

y = -2/3 x + 5/3

Step-by-step explanation:

y = mx + b

y = -2/3 x + b

1 = -2/3 × 1 + b

3/3 + 2/3 = b

b = 5/3

y = -2/3 x + 5/3

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Alexus [3.1K]

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Elza [17]

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Paraphin [41]

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Snezhnost [94]

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$y - 0 = \frac{2}{3}(x - 3)$

Hope this helps! :) Hope this Helps!

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sukhopar [10]

take a factor of 6 out to make 6(4x-3)

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