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3 years ago

(40/5)-7+2? I know the answer but I don’t know how I got to it

Mathematics

2 answers:

ExtremeBDS [4]3 years ago

8 0

Answer:

Step-by-step explanation:

(40/5)-7+2

PEMDAS says parentheses first, so divide inside the parentheses

(8)-7+2

Then add and subtract from left to right

1 +2

marishachu [46]3 years ago

3 0

Answer:

Step-by-step explanation:

Using PEMDAS:

(40/5)-7+2

- > 40/5 - 8

8 - 7 + 2

1 + 2

Hope this helps you.

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I NEED HELP ASAP!!!!! WILL MARK BRAINLIEST!!!!!!

alexgriva [62]

Answer: 16

Step-by-step explanation:

The 7 and the 9.

Look closely

5 0

3 years ago

Find the value of x. (2 points each) 9x=2x+14

kumpel [21]

Answer:

x = 2

Step-by-step explanation:

Given

9x = 2x + 14 ( subtract 2x from both sides )

7x = 14 ( divide both sides by 7 )

x = 2

5 0

4 years ago

Use the t-distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from r

Sergio [31]

Answer:

(A) The value of t test statistics is 2.767 and P-value is 0.0042.

(B) We conclude that the mean of first group is greater than the mean of second group.

Step-by-step explanation:

We are given the following hypothesis below;

Null Hypothesis, $H_0$ : $\mu_1=\mu_2$ {means that the mean of first group is equal to the mean of second group}

Alternate Hypothesis, $H_A$ : $\mu_1>\mu_2$ {means that the mean of first group is greater than the mean of second group}

The test statistics that would be used here Two-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ~ $t__n__1-_n__2-2$

where, $\bar X_1$ = sample mean of first group = 56

$\bar X_2$ = sample mean of second group = 51

$s_1$ = sample standard deviation of first group = 8.2

$s_2$ = sample standard deviation of second group = 6.9

$n_1$ = sample of first group = 30

$n_2$ = sample of second group = 40

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2} +(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(30-1)\times 8.2^{2} +(40-1)\times 6.9^{2} }{30+40-2} }$ = 7.482

So, the test statistics = $\frac{(56-51)-(0)}{7.482 \times \sqrt{\frac{1}{30} +\frac{1}{40} } }$ ~ $t_6_8$

= 2.767

(A) The value of t test statistics is 2.767.

Also, P-value of the test statistics is given by;

P-value = P( $t_6_8$ > 2.767) = 0.0042

(B) Now, at 10% significance level the t table gives critical value of 1.295 at 68 degree of freedom for right-tailed test.

Since our test statistic is more than the critical values of t as 2.767 > 1.295, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean of first group is greater than the mean of second group.

8 0

3 years ago

Identify the horizontal asymptote of the graph of f(x) = 5^x

Anna [14]

Answer: x=25

*explenation*
5^=5+5+5+5+5= 25

4 0

3 years ago

A clerical worker takes 2 times as long to finish a job as it does an executive secretary. Working together, it takes them 6 hr

malfutka [58]

Answer:

<h2>18 hours</h2>

Step-by-step explanation:

This problem is on Combined work rate

Step one:

given data

let the secretary take x hours to finish one job

so the clerical worker will take 2x hours to finish one job.

Both of them working together will take 6 hours

Step two:

The combined work formula is

T/A+T/B=1

Where T= time working together

A= time the Clerical worker spent alone

B= time the secretary spent alone

substituting we have

6/2x+6/x=1

solve for x

6+12/2x=1

18/2x=1

9/x=1

cross multiply

x=9 hours

the clerical worker take 2x hours

2*9= 18 hours

3 0

3 years ago