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sleet_krkn [62]
3 years ago
15

A. p = 5t + 4 b. a = t2 - 4 c. d = t(5 – f) Make t the subject in the formulas

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0

Answer:

a, t = (p - 4)/5

b. t =√(a + 4)

c. t = d/(5-f)

Step-by-step explanation:

a. p = 5t + 4

To make t the subject of the equation, subtract 4 from both sides

p - 4 = 5t + 4 - 4

p - 4 = 5t

Divide both sides by 5

(p - 4)/5 = t

t = (p - 4)/5

b. a = t2 - 4

to make t the subject, add 4 to both sides

a + 4 = t2 - 4 + 4

a + 4 = t2

find the root of both sides

t =√(a + 4)

c. d = t(5 – f)

to make t the subject, divide both sides by 5 - f

d/(5-f) = t(5 – f)/(5 – f)

t = d/(5-f)

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They have a rectangle ABCD as shown below, where AB = 24cm BC = 10cm and AE = 13cm
alex41 [277]

Answer:

A. Area of ABCD = 240 cm^{2}

B. 60 cm

C. 36 cm

D. 50 cm

Step-by-step explanation:

Given: AB = 24cm BC = 10cm and AE = 13cm.

A.  Since a rectangle is a 2 dimensional figure, it has no volume but area.

So that,

the area of the rectangle ABCD = length x width

                                                     = 24 x 10

                                                     = 240 cm^{2}

B. To calculate the circumference of the BCD triangle, apply the Pythagoras theorem to determine BD.

BD^{2} = BC^{2} + DC^{2}

       = 10^{2} + 24^{2}

       = 676

BD = \sqrt{676}

     = 26

BD = 26 cm

so that,

the circumference of BCD = 10 + 24 + 26

                                         =   60 cm

C. To calculate the circumference of the BEC triangle,

AC = 26 cm, AE = 13 cm

CE = 26 - 13

     = 13 cm

CE = 13 cm

The circumference of the BEC triangle = 13 + 13 + 10

                                                                 = 36 cm

D. The circumference of the DEC triangle = 13 + 13 + 24

                                                                 = 50 cm

       

7 0
3 years ago
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