Question

8th grade math . Pythagorran practice ​

Answer 1

The answers according to rows are:

• ROW 1 : diameter of base = 10,  base area = 25π, volume of cylinder = 175π    volume of cone = $\frac{175}{3}$π

• ROW 2 : base radius = 3, base area = 9π, height = 40/3, volume of cylinder = 120π
• ROW 3 : base radius = 6, base diameter = 12, height = 4, volume of cylinder = 144π

What is mensuration?

Mensuration is an aspect of geometry that deals with measurement of volumes and area.

Analysis:

Row 1

Diameter of base = 2 x radius = 2 x 5 = 10

Base area = π$r^{2}$ = π$(5)^{2}$ = 25$\pi$

Volume of cylinder = base area x height = 25π x 7 = 175π

Volume of cone  = 1/3 x volume of cylinder = 175π/3

Row 2

Base radius = base diameter/2 = 6/2 = 3

Base area = π$r^{2}$ = π$(3)^{2}$ = 9π

Volume of cone = 1/3 x base area x height

base area x height  = 3 x volume of cone

base area x height = 3 x 40π

Height = 120π/9π = 40/3

Cylinder volume = 3 x cone volume = 3 x 40π = 120π

Row 3

Base area = π$r^{2}$

36π =  π$r^{2}$

r2 = $\sqrt{36}$

r = 6

Base diameter = 2 x 6 = 12

Volume of cone  = 1/3 x base area x height

48π = 1/3 x 36π x height

Height = 4

Cylinder volume = 3 x 48 = 144π

In conclusion,

ROW 1 : diameter of base = 10,  base area = 25π, volume of cylinder = 175π

volume of cone = $\frac{175}{3}$π

ROW 2 : base radius = 3, base area = 9π, height = 40/3, volume of cylinder = 120π

ROW 3 : base radius = 6, base diameter = 12, height = 4, volume of cylinder = 144π

Learn more about mensuration: brainly.com/question/18541562

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