Length of rectangle is 1 unit
<u>Solution:
</u>
Given that
Length of a rectangle is width minus 8 units.
Area of rectangle = 9 square units
Need to calculate the length of rectangle.
Let us assume width of rectangle = x
As Length is width minus 8,
Length of the rectangle = x – 8



As given that area of rectangle = 9 square units

On solving above quadratic equation for x, we get

When 
When
As width cannot be negative, so considering x = 9

Hence, Length of rectangle is 1 unit.