and 
. So we have a remainder of
and 
. Subtracting this from the previous remainder gives a new remainder
and 
. Subtracting this from the previous remainder gives a new one of
and we're done since 2 does not divide 
. So we have
Answer:
i lost lots of pts so i had to do it bro
Step-by-step explanation:
im really sorry bb
Answer:
x = -36, y = 6, z = -6
Step-by-step explanation:
The requirement x/z = -z means x = -z².
The requirement x/y = z means x = yz.
These two requirements together mean yz = -z², or y = -z.
The requirements that z/2 and z/3 are integers mean that z is a multiple of 2·3 = 6. The smallest magnitude non-zero multiple is z=-6 (since we also require z < -z).
Using z=-6, we have x = -z² = -36; y = -(-6) = 6.
For some positive integer n, ...
... x = -36n², y = 6n, z = -6n.
Answer:
4 is in the p and 2 in the not p
Step-by-step explanation:
the one with the 40 in p the one with the 12 in p the one with 8 in the p and the one with the 12 with a 3 is in the p the others are in no p.
Answer:
5 and 7
Step-by-step explanation:
5 and 7 are the nearest integers, and 6 is right in between them
