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const2013 [10]
2 years ago
12

The graph below shows the cost of pens based on the number of pens in a pack. What would be the cost of one pen?

Mathematics
1 answer:
olga nikolaevna [1]2 years ago
7 0

9514 1404 393

Answer:

  A.  $1.50

Step-by-step explanation:

You can probably read the cost from the graph. Find the x-axis position corresponding to 1 pen and locate the point on the graph above that position. Then read the y-coordinate (cost) from the vertical axis. It will be sufficiently close to $1.50 that you can easily determine that to be the correct answer choice.

__

Cost per pen is found by dividing cost by pens.

  $4.50/(3 pens) = $1.50 /pen*

_____

* /pen would be pronounced, "per pen."

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3. Here is a list of exam scores for Mr. Kraft's calculus class:
Alja [10]

Answer

15%

Step-by-step explanation:

I think the answer is 15% because when we talk about percentile, we are actually subtracting from 100% in simpler terms. If we say a 85th percentile, it actually means 15%.

4 0
3 years ago
HELP PLEASEEE 9th Grade Geometry
Shtirlitz [24]

Step-by-step explanation:

AD ≅ BC, Given

∠BCD ≅ ∠ADC, Given

CD ≅ CD, Reflexive property

ΔBCD ≅ ΔADC, SAS congruence

∠BDC ≅ ∠ACD, CPCTC

ΔECD is an isosceles triangle, definition of isosceles

DE ≅ CE, properties of isosceles triangles

6 0
3 years ago
If sin theta = 4/5 and theta is in quadrant 2, the value of cot theta is
trasher [3.6K]

Answer:

Cot(theta) = - 0.75 or -3/4

Step-by-step explanation:

The hypotenuse is 5

The y value is 4

We need to find the corresponding x value.

x^2 + y^2 = z^2

X = ?

y = 4

z = 5

x^2 + 4^2 = 5^2

x^2 + 16 = 25

x^2 = 9

Now in this case, you are in quadrant 2, so the x value is - 3

sqrt(x^2) = sqrt(9)

x = - 3

The cot value is the adjacent (x value) / the opposite ( y ) value

Cot(theta) = -3/4

cot(theta) = -0.75

8 0
3 years ago
Read 2 more answers
Find the value of x which ABCD must be a parallellogram?<br> x =
aev [14]
If\ ABCD\ is\ a\ parallelogram,\ then\\\\2x-1=x+3\ \ \ |add\ 1\ to\ both\ sides\\\\2x=x+4\ \ \ \ |subtract\ x\ from\ both\ sides\\\\\boxed{x=4}
3 0
3 years ago
The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0
3 years ago
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