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3 years ago

What kind of number is a negative number?

Mathematics

1 answer:

ziro4ka [17]3 years ago

7 0

Negative number is a number that is less than zero

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Very buys a basket of mangoes that is priced $14 before tax. The sales tax is 6%. What is the total price Avery pays for t

igor_vitrenko [27]

Answer:

Avery needs to pay $14.84

Step-by-step explanation:

When there's a tax we need to sum the original value of the product with the tax's value. To find the amount of money Avery needs to pay in taxes we can apply a rule of three as shown below:

$\frac{14}{x} = \frac{100}{6} \frac{\%}{\%}$

Where "x" is the tax value, and $14 represents 100%, since it's the value used to calculate the tax. We have:

$x = \frac{14*6}{100}\\x = \frac{84}{100}\\x = 0.84$

The value to be paid is the product value plus the tax, therefore:

$\text{paid} = 14 + 0.84 = 14.84$

Avery needs to pay $14.84

6 0

3 years ago

Which graph represents the solution set of this inequality?

lesya692 [45]

Answer:

the answer is C

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What's $10,100 Afghanistan converted into US$ <br><br> Please answer with how you got your answer

Wewaii [24]

Hi :)

10, 100 Afghani Afghani (currency name) is $1212 USD with the conversion you provided. Today it's like $117.41.

7 0

3 years ago

EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =

geniusboy [140]

The Lagrangian,

$L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)$

has critical points where its partial derivatives vanish:

$L_x=1-\lambda-2\mu x=0$

$L_y=2+\lambda-2\mu y=0$

$L_z=9-\lambda=0$

$L_\lambda=x-y+z-1=0$

$L_\mu=x^2+y^2-1=0$

$L_z=0$ tells us $\lambda=9$ , so that

$L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu$

$L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}$

Then with $L_\mu=0$ , we get

$x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2$

and $L_\lambda=0$ tells us

$x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}$

Then there are two critical points, $\left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right)$ . The critical point with the negative $x$ -coordinates gives the maximum value, $9+\sqrt{185}$ .