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3 years ago

What kind of number is a negative number?

Mathematics

1 answer:

ziro4ka [17]3 years ago

7 0

Negative number is a number that is less than zero

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lisov135 [29]

C- picture frames per box

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3 years ago

What is the value of z for the parallelogram shown? A.130 B.40 C.10 D.26

galben [10]

Z=10 because the opposite side is 50 degrees so the 5z=50

If you solve, z=10

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3 years ago

Read 2 more answers

Solve for x: x^2 + 28x = 60

Alisiya [41]

For this case we have a quadratic equation, $x ^ 2 + 28x-60 = 0$ , of the form $ax ^ 2 + bx + c = 0$

Where:

$a = 1\\b = 28\\c = -60$

We can solve the equation by factoring, that is, we bias two numbers that multiplied give as a result -60 and added as a result 28.

These numbers are:

$+30\ and\ -2\\+ 30-2 = + 28\\+ 30 * -2 + -60$

Then, the factorization is given by:

$(x-2) (x + 30) = 0$

The roots are:

$x_ {1} = 2\\x_ {2} = - 30$

Answer:

$x_ {1} = 2\\x_ {2} = - 30$

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3 years ago

|x − 5| − |2 − x| + |x + 1| , if x ≥ 5

son4ous [18]

Answer:

9990% 222$

Step-by-step explanation:

if you work it will help u head

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3 years ago

Fill in the blanks below to make a true statement. In a binomial experiment with n trials and probability of success p, if np (1

Sergeu [11.5K]

Answer:

$\mu_{x}=np$

$\sigma^2_{X}=np(1-p)$

Step-by-step explanation:

∵ When x is a random variable having distribution B(n, p), then for sufficiently large value of n, the following random variable has a standard normal distribution,

$\frac{x-\mu}{\sigma}\sim N(0,1)$

Where,

$\mu=np$

$\sigma^2=np(1-p)$

Here the variable X has a binomial distribution,

Such that, np (1 - p) ≥ 10 ⇒ n is sufficiently large.

Where, n is the total numbers of trials, p is success in each trials,

So, the mean of variable X is,

$\mu_{X} = np$

And, variance of variable X is,

$\sigma^2{X}=np(1-p)$

3 0

3 years ago