Question

A large bag of marbles contains an equal amount of red, orange, yellow, blue, and green marbles. Brody randomly selects 1 marble from the bag. Which of the following represents the probability of selecting a red, blue, yellow, or green marble
A) 0.8
B) 0.7
C) 0.9
D) 0.6

Answer 1

Answer:  The correct option is (A) 0.8.

Step-by-step explanation:  Given that a  large bag of marbles contains an equal amount of red, orange, yellow, blue, and green marbles. Brody randomly selects 1 marble from the bag.

We are to find the probability of selecting a red, blue, yellow or green marble.

Let n be the number of each color of marbles in the bag.

That is, the number of red, orange, yellow, blue, and green marbles, each equals n.

Let S denote the sample space of selecting a marble from the bag and A denote the event of selecting a red, blue, yellow or green marble.

Then, we have

n(S) = n + n + n + n + n = 5n,

n(A) = n + n + n + n = 4n.

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{4n}{5n}=\dfrac{4}{5}=0.8.$

Thus the required probability selecting a red, blue, yellow or green marble is 0.8.

Option (A) is CORRECT.

Answer 2

The answer will be
$\frac{4}{5} = 0.8$
hope this helps