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KiRa [710]
1 year ago
15

Look at the number line below.

Mathematics
1 answer:
forsale [732]1 year ago
4 0

Answer:

-1.166666667

Step-by-step explanation:

Since there are five lines in between -2 and -1 you need to divide 1 by 6 and when you do that you get .166666667. Since the point is on the first line you add that to one to get 1.166666667 and since it is on the negative side of the number line the number has to be negative.

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X + 67 = 70 <br><br> what does "x" equal?<br><br> Please explain your answer, thanks!
8_murik_8 [283]
Hey there!

3 + 67 = 70,

so your answer will be:
x = 3

Hope this helps!
Have a great day (:
5 0
3 years ago
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Consider the function shown.
Vanyuwa [196]

Answer:

Decreasing from x = 1 to x = 6.

Step-by-step explanation:


4 0
3 years ago
Jason wants to buy a game that cost $20. He earns $2 every time he washes the
Reika [66]

Answer:

7

Step-by-step explanation:

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7 0
2 years ago
How many times must we toss a coin to ensure that a 0.95-confidence interval for the probability of heads on a single toss has l
musickatia [10]

Answer:

(1) 97

(2) 385

(3) 9604

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The margin of error in this interval is:

MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The formula to compute the sample size is:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}

(1)

Given:

\hat p = 0.50\\MOE=0.1\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.1^{2}}\\=96.04\\\approx97

Thus, the minimum sample size required is 97.

(2)

Given:

\hat p = 0.50\\MOE=0.05\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.05^{2}}\\=384.16\\\approx385

Thus, the minimum sample size required is 385.

(3)

Given:

\hat p = 0.50\\MOE=0.01\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.01^{2}}\\=9604

Thus, the minimum sample size required is 9604.

8 0
2 years ago
What is the value of x?
antoniya [11.8K]
Since the figure is a rhombus, the diagonals cut each other at right-angles and bisect each other, namely cut their vertices in equal halves.

what the dickens does all that mean?  well, the angles at vertex C and vertex A are all twins, and therefore, ∡BCA = x, therefore

\bf (3x-26)+(x)+(90)=180\implies 4x+64=180\implies 4x=116&#10;\\\\\\&#10;x=\cfrac{116}{4}\implies x=29
5 0
3 years ago
Read 2 more answers
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