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Helen [10]
2 years ago
9

Please help me with my hw

Mathematics
1 answer:
stellarik [79]2 years ago
6 0
Part 2 is 12.5 cm represents 5km
I worked this out by doing a ratio
5cm=2km
?cm=5km
you have to do 2 times 2.5 to get 5km so you do 5 times 2.5 to get 12.5cm
so the answer is that 12.5cm
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the amount of each payment to be made into a sinking fund which earns 9​% compounded quarterly and produces ​$43 comma 000 at th
Blizzard [7]

Answer:

$2647.18

Step-by-step explanation:

Data provided in the question:

Rate = 9% compounded quarterly

interest rate per period, i = 9% ÷ 4 = 2.25% = 0.0225

Future value = $43,000

Time = 3.5 years

Number of periods,  = 3.5 × 4 = 14

Now,

Let the annual payments be 'A'

Thus,

Future value = A × [ (1 + i)ⁿ - 1 ) ÷ i ]

or

$43,000 = A × [ (1 + 0.0225)¹⁴ - 1 ) ÷ 0.0225 ]

or

$43,000 = A × 16.244

or

A = $2647.18

6 0
2 years ago
Calculate the radius of the circular rug. Use 3.14 for π. <br><br> area of rug: 153.86 feet
irakobra [83]

Answer:

7 ft

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

153.86 = 3.14 r^2

Divide each side by 3.14

153.86 / 3.14 = r^2

49 = r^2

Take the square root of each side

sqrt(49) = sqrt(r^2)

7 = r

5 0
3 years ago
Read 2 more answers
When 10 gallons of gasoline are put into a car's tank, the indicator goes from 1/8 of a tank to 3/4. What is the total capacity
juin [17]
It should be 16 gallons.
7 0
3 years ago
What is the opposite of -3
Rama09 [41]
Positive 3
It’s positive three
6 0
3 years ago
Read 2 more answers
Consider the following frequency distribution.
Zarrin [17]

Answer:

Class interval                            10-19 20-29 30-39 40-49 50-59

cumulative frequency               10      24       41        48       50

cumulative relative frequency 0.2   0.48     0.82    0.96      1

Step-by-step explanation:

1.

We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.

Cumulative frequency

10

10+14=24

14+17=41

41+7=48

48+2=50

sum of frequencies is 50 so the relative frequency is f/50.

Relative frequency

10/50=0.2

14/50=0.28

17/50=0.34

7/50=0.14

2/50=0.04

Cumulative relative frequency

0.2

0.2+0.28=0.48

0.48+0.34=0.82

0.82+0.14=0.96

0.96+0.04=1

The cumulative relative frequency is calculated using relative frequency.

Relative frequency is calculated by dividing the respective frequency to the sum of frequency.

The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.

The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.

4 0
3 years ago
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