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2 years ago

Please help me quick!

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

6 0

Answer:

transition 1 would be 5 to the right

transition 2 would be 1 down

Step-by-step explanation:

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Find the product.<br><br> y4 · y6

Vanyuwa [196]

Answer:

$y^{10}$

Step-by-step explanation:

I am assuming that you mean $y^4*y^6$ .

$y^4*y^6\\\text {Apply the product rule: } a^n*a^m =a^{n+m}\\4 + 6 = 10\\\text {Therefore,}\\\boxed {y^4*y^6 = y^{10}}$

<em>Brainilest Appreciated.</em>

4 0

3 years ago

Read 2 more answers

14.

romanna [79]

1. C
2.D
3.A
4.B
Hope this helps!

5 0

3 years ago

The diameter of a circle is ___________the length of its radius?

serg [7]

Answer:

Twice the length of the radius

Step-by-step explanation:

A radius by definition is half of the diameter which means the diameter is twice the radius.

8 0

2 years ago

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago

Choose the point-slope form of the equation below that represents the line that passes through the points (-6, 4) and (2, 0).

Arte-miy333 [17]

Point slope form
y-y1=m(x-x1)
slope=m
a point is (x1,y1)

slope=(y2-y1)/(x2-x1)
given
(-6,4) and (2,0)
slope=(0-4)/(2-(-6))=-4/(2+6)=-4/8=-1/2

a point is (-6,4)
x1=-6
y1=4

y-4=-1/2(x+6)
not listed

5 0

3 years ago