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Kipish [7]
3 years ago
8

HELP! EASY! Fill in the blanks!

Mathematics
1 answer:
Over [174]3 years ago
7 0
  1. 8points
  2. 9lines
  3. 5planes
  4. D-G-F
  5. ACDF
  6. AC
  7. DE
  8. BE
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If $300 is invested at a rate of 6% per year and is compounded quarterly, how much will the investment be worth in 12 years?
MAXImum [283]

Answer:

$613.04

Step-by-step explanation:

<em>Compound Interest Formula:</em>

   A = P(1+\frac{r}{n})^{nt}

   n = number of compounds

   t = time

   r = interest rate

   P = principle amount (original amount)

   A = final amount

Since it's compounded quarterly, that means there will be 4 compounds per year, so n=4. The interest rate has to be converted to the decimal value, and this is done by simply dividing it by 100 to get r=0.06.

Plug Values into equation:

A = 300(1+\frac{0.06}{4})^{12*4}

Simplify inside parenthesis

A = 300(1.015)^{48}

Calculate exponent

A \approx 300(2.043478)

Multiply values

A \approx 613.04348

Round

A = 613.04

7 0
2 years ago
Help this is worth 20 points!!
My name is Ann [436]
It takes 59 earth days to rotate and 88 earth days to fully orbit the sun
3 0
3 years ago
I just need help solving this problem. Also please don't put the answer into a file because I can't open them. It's also really
dem82 [27]

Answer:

<em>31° </em>

Step-by-step explanation:

5 0
3 years ago
How to solve for 6x-12+2x=3+8x-15
Alecsey [184]
6x−12+2x=3+8x−15

Simplify:

6x+−12+2x=3+8x+−15

(6x+2x)+(−12)=(8x)+(3+−15)(Combine Like Terms)

8x+−12=8x+−12


8x−12=8x−12

Subtract 8x from both sides.

8x−12−8x=8x−12−8x

−12=−12

Add 12 to both sides.

−12+12=−12+12

0=0

The real numbers are the only solution we can have.


4 0
3 years ago
Consider the roots of a cubic equation with integral coefficients: −1, −4, and 3. Which choice is a factor of the cubic equation
mash [69]

Answer:

D

Step-by-step explanation:

Lets go case by case.

Given the roots, a factor will be part of the equation if for some of the roots the factor becomes null, i.e., equal to 0.

Is there any root that makes (x+3)=0? No, as it only becomes 0 for x = - 3 and -3 is not a root. So A NO!

Is there a root that makes (x-1)=0? No, as it only becomes 0 for x=1 and 1 is not a root. So B NO!

(x-4)=0 only for x=4, and as 4 is not a root, C NO!

The last, (x-3)=0 if x=3. As 3 is one of the roots, (x-3) is a factor of our equation!

D is the only correct option!

5 0
3 years ago
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