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nataly862011 [7]
2 years ago
13

Find a quadratic equation which has double root = 9. Write the quadratic form in the simplest standard form? x^2 +bx+c.

Mathematics
1 answer:
yarga [219]2 years ago
7 0

The quadratic equation for an equation with double roots 9 is : x^{2}-18x+81 = 0.

what is a Quadratic equation?

A quadratic equation is an Algebraic equation with the highest power of its variable as 2.

It can be solved by several methods : Factorization, completing the square and graphical methods.

Analysis

if 9 is the double root of the equation, it means x = 9 or  x = 9

So (x-9)(x-9) are factors

Therefore,

(x-9)(x-9) = 0

x^{2} - 9x-9x + 81 = 0

x^{2} -18x+81 = 0

in conclusion, the quadratic equation of the double root 9  is:  x^{2} -18x+81 = 0

Learn more about Quadratic equations : brainly.com/question/1214333

#SPJ1

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mamaluj [8]
The correct answer is D.

Have a great day!
3 0
2 years ago
A certain circle can be represented by the following equation. x^2+y^2+18x+14y+105=0 What is the center of the circle? What is t
Gre4nikov [31]

Answer:

See below.

Step-by-step explanation:

Recall the equation for a circle:

(x-h)^2+(y-k)^2=r^2, where (h,k) is the center and r is the radius.

We need to turn the given equation into the above format. We do this by completing the square.

First, group them:

(x^2+18x)+(y^2+14y)=-105

For the first section, complete the square for x^2+18x:

x^2+18x+81-81

(x+9)^2-81

Do the same for the second:

y^2+14y

y^2+14y+49-49

(y+7)^2-49

All together:

((x+9)^2-81)+((y+7)^2-49)=-105

(x+9)^2+(y+7)^2-130=-105

(x+9)^2+(y+7)^2=25

The center is (-9,-7).

The radius is \sqrt{25}=5

5 0
3 years ago
48:23 +4.10 3/4<br> Help pls....
Bond [772]

Answer:

48:26.075

Step-by-step explanation:

4 0
3 years ago
Show how to solve 1/4 (4 + x) = 4/3<br><br><br><br> pls solve for 2 brainliest
Thepotemich [5.8K]
Simplify
1
4
(
4
+
x
)
4
1
​
(4+x) to
4
+
x
4
4
4+x
​
.
4
+
x
4
=
4
3
4
4+x
​
=
3
4
​


2 Simplify
4
+
x
4
4
4+x
​
to
1
+
x
4
1+
4
x
​
.
1
+
x
4
=
4
3
1+
4
x
​
=
3
4
​


3 Subtract
1
1 from both sides.
x
4
=
4
3
−
1
4
x
​
=
3
4
​
−1

4 Simplify
4
3
−
1
3
4
​
−1 to
1
3
3
1
​
.
x
4
=
1
3
4
x
​
=
3
1
​


5 Multiply both sides by
4
4.
x
=
1
3
×
4
x=
3
1
​
×4

6 Simplify
1
3
×
4
3
1
​
×4 to
4
3
3
4
​
.
x
=
4
3
x=
3
4
​
4 0
3 years ago
Find mZDCE.
svetlana [45]

Answer: C

Step-by-step explanation: Hope this help :D

6 0
3 years ago
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