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Exterior angle c = the sun of the two opposite interior angles a and b.
10x -23 = 5x -17 + 7x -26
Combine the right side:
10x -23 = 12x -43
Add 43 to both sides:
10x +20 = 12x
Subtract 10x from both sides:
20 = 2x
Divide both sides by 2
X = 10
Now you have x replace it in the equation for A:
A = 5x -27 = 5(10) -27 = 50-27 = 23
Angle A = 23 degrees.
933.33 x 933.33 is ypur answer to maximize area
Answer:
A. 162 m²
Step-by-step explanation:
==>Given:
Isosceles trapezoid with:
base a = 19m
base b = 35m
Perimeter = 74meters
==>Required:
Area of trapezoid
==>Solution:
Recall: the length of the legs of an isosceles trapezoid are equal.
Perimeter of isosceles trapezoid = sum of the parallel sides + 2(length of a leg of the trapezoid)
Let l = leg of trapezoid.
Perimeter = 74m
Sum of parallel sides = a+b = 19+35 = 54m
Thus,
74 = 54 + 2(l)
74 - 54 = 2(l)
20 = 2(l)
l = 20/2 = 10m
Let's find area:
Area = ½(a+b)*h
a = 19
b = 35
h = ?
Using Pythagorean theorem, let's find h as follows:
h² = l² - [(35-19)/2)²
h² = 10² - [16/2]²
h² = 100 - 64
h² = 36
h = √36 = 6m
Area = ½ x (a+b) × h
= ½ × (19+35) × 6
= ½ × 54 × 6
= 27 × 6
Area = 162m²
Answer:
3rd
Step-by-step explanation:
