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monitta
3 years ago
15

Question: Add the decimals591.79+528.192 =312.7+2.566 = 235.977+61.889​

Mathematics
2 answers:
SashulF [63]3 years ago
5 0

Answer:

1. 1119.982

2. 315.266

3. 297.866

RideAnS [48]3 years ago
3 0

Answer:

1. 1119.982

2. 315.266

3. 297.866

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Help me with this!!! I will mark Brainliest
Maurinko [17]

Answer:

No

Step-by-step explanation:

VX = 4 spaces

UW = 3 spaces

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3 years ago
The problem has been started for you.
WITCHER [35]

Answer:

its to find the quotient, start by dividing 25 into 1658

Step-by-step explanation:

for the following question its 66.32 and 66 8/25 (hope this helps bud)

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The cost of printing a catalog of the products that your company distributes is a flat rate of $52 plus $0.20 per copy. Let C re
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7 0
3 years ago
What is the percentage of cacao in hot chocolate which is made of 480 grams of milk and 20 grams of cacao?
galina1969 [7]

Given that the hot chocolate is made of 480 grams of milk and 20 grams of cacao.

We need to determine the percentage of cacao in hot chocolate.

<u>The percentage of cacao:</u>

The total grams of hot chocolate can be determined by adding the total grams of milk and the total grams of cacao.

Total grams of hot chocolate = Grams of Milk + Grams of cacao

Total grams of hot chocolate = 480 + 20 = 500 grams.

Thus, the total grams of hot chocolate is 500 grams.

Now, we shall find the percentage of cacao.

The percentage of cacao is given by

\frac{100}{500}\times 20

Simplifying, the values, we get,

\frac{2000}{500}=4\%

Thus, the percentage of cacao is 4%

6 0
3 years ago
In a random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand. C
horrorfan [7]

Answer:

<em>90% confidence interval for the proportion of fans who bought food from the concession stand</em>

(0.5603,0.6529)

Step-by-step explanation:

<em>Step(i)</em>:-

<em>Given sample size 'n' =300</em>

Given data  random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand.

<em>Given sample proportion </em>

<em>                        </em>p^{-}  = \frac{x}{n} = \frac{182}{300} =0.606

level of significance = 90% or 0.10

Z₀.₁₀ = 1.645

<em>90% confidence interval for the proportion is determined by</em>

(p^{-} - Z_{0.10}\sqrt{\frac{p(1-p)}{n} }  , p^{-} +Z_{0.10}\sqrt{\frac{p(1-p)}{n} })

(0.6066 - 1.645\sqrt{\frac{0.6066(1-0.6066)}{300} }  ,0.6066+1.645\sqrt{\frac{0.6066(1-0.6066)}{300} })

(0.6066 -  0.0463  ,0.6066 +  0.0463)

(0.5603,0.6529)

<u>final answer</u>:-

<em>90% confidence interval for the proportion of fans who bought food from the concession stand</em>

(0.5603,0.6529)

5 0
3 years ago
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