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1 year ago

The point {-1,5} is reflected over the y-axis. Where is the location of the new

Mathematics

1 answer:

Monica [59]1 year ago

6 0

Answer:

B (1, 5)

Step-by-step explanation:

When a point is reflected over an axis, the coordinate which corresponds to that axis does not change. The other coordinate becomes negative with respect to the current value.

Hence, since the y-axis is mentioned, the y-coordinate does not change and the x-coordinate becomes negative.

New point = (-(-1), 5)
New point = (1, 5)
Option B

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Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4

vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

$c^2 = 4^2 + 6^2$

$c^2 = 16 + 36$

$c^{2}$ = 52

Pythagoras' theorem for the middle one :

$b^{2}$ = $6^{2}$ + $a^{2}$

Pythagoras' theorem for the biggest one :

$(4+a)^2 = c^2 + b^2$

$16 + 8a + a^2 = 52 + b^2$

Using the formula before (for $b^2$ ) it becomes :

$16 + 8a + a^2 = 52 + (6^2 + a^2)$

$16 + 8a + a^2 = 52 + 6^2 + a^2$

$16 + 8a = 52 + 6^2$

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

$a = \frac{72}{8}$

a = 9

Verifying :

$b^2 = 6^2 + a^2$

$b^2 = 36 + 81$

$b^2 = 117$

$b^{2}$ = 117

The biggest one :

$(4+a)^2 = c^2 + b^2$

$(4+9)^2 = 52 + 117$

$13^2 = 169$

True

8 0

2 years ago

A man standing on level ground is 1000 feet away from the base of a 350-foot-tall building. Find,

CaHeK987 [17]

If you sketch the man and the building on paper, you'll have a
right triangle. The right angle is the point where the wall of
the building meets the ground. The height of the building
is one leg of the triangle, the line on the ground from the
building to the man's feet is the other leg, and the line
from his feet to the top of the building is the hypotenuse.

We need to find the angle at his feet, between the hypotenuse
and the leg of the triangle.

Well, the side opposite the angle is the height of the building -- 350ft,
and the side adjacent to the angle is the distance from him to the
building -- 1,000 ft.

The tangent of the angle is (opposite) / (adjacent)

= (350 ft) / (1,000 ft) = 0.350 .

To find the angle, use a book, a slide rule, a Curta, or a calculator
to find the angle whose tangent is 0.350 .

tan⁻¹(0.350) = 19.29° . (rounded)

3 0

3 years ago

−2x (x + 5 ) for x = −3

ValentinkaMS [17]

Answer:

Step-by-step explanation:

(-2)(-3)(-3+5)

6(2)

Merry Christmas :)

4 0

2 years ago

Solve the equation. Please show your math work. <br> 2/3A  24 <br> Answer:

Korvikt [17]

What is the ribbon thing for?

4 0

3 years ago

A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream. What is the rate of

nikitadnepr [17]

<h3>Rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr</h3><h3><u>Solution:</u></h3>

Given that,

A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream

Therefore,

Upstream distance = 165 km

Upstream time = 3 hours

<h3><u>Find upstream speed:</u></h3>

$speed = \frac{distance}{time}\\\\speed = \frac{165}{3}\\\\speed = 55$

Thus upstream speed is 55 km per hour

Downstream distance = 510 km

Downstream time = 6 hours

<h3><u>Find downstream speed:</u></h3>

$speed = \frac{510}{6}\\\\speed = 85$

Thus downstream speed is 85 km per hour

<em><u>If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then</u></em>

Speed downstream = u + v km/hr

Speed upstream = u - v km/hr

Therefore,

u + v = 85 ----- eqn 1

u - v = 55 ----- eqn 2

Solve both

Add them

u + v + u - v = 85 + 55

2u = 140

u = 70

<em><u>Substitute u = 70 in eqn 1</u></em>

70 + v = 85

v = 85 - 70

v = 15

Thus rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr

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3 years ago