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7nadin3 [17]
3 years ago
7

What number must be subtracted from -5 for the difference to be -2. Explain your answer.​

Mathematics
1 answer:
tester [92]3 years ago
3 0

Answer:

-3

Step-by-step explanation:

Let n be a number

Rewrite the sentence into something that can be interpreted better:

A number subtracted from -5 is -2

Now you can translate the statement into an equation:

-5 - n = -2

Solve for n

-n = 3

n = -3

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Diane ande her 3 friends when out to eat the total cost of lunch was $34 if they split the bill evenly how much Will each person
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8.5

Step-by-step explanation:

34 divided by 4

4 0
3 years ago
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Y = x + 2<br> y = 2x - 5<br> what is x and y
lana66690 [7]

Answer:

x= 7 y= 9 (7,9)

Step-by-step explanation:

solve by using system if equations. multiply top answer by 2, giving u 2y=2x+4 and y=2x-5 subtract the equations. y=9 (the x cancels out) then put 9 in for y. 9=x+2. subtract 2. giving u 7. and now x =7

7 0
2 years ago
Can someone solve this
Brut [27]

Answer:

8 and 17

Step-by-step explanation:

6 0
3 years ago
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One of the legs of a right triangle measures 12 cm and the other leg measures 13 cm find the measure of the hypotenuse if necess
Amanda [17]

Answer:

17.7 cm

Step-by-step explanation:

One of the legs of a right triangle measures 12 cm and the other leg measures 13 cm find the measure of the hypotenuse if necessary round the nearest 10th

To find the Hypotenuse of a right angle triangle, we solve using Pythagoras Theorem

Hypotenuse ² = Opposite ² + Adjacent ²

Hypotenuse = √Opposite ² + Adjacent ²

Opposite = 12 cm

Adjacent = 13 cm

Hence,

Hypotenuse = √12² + 13²

= √144 + 169

= 17.691806013 cm

Approximately = 17.7 cm

Therefore, the measure of the Hypotenuse is 17.7 cm

6 0
3 years ago
Find the complex fourth roots of 81(cos(3pi/8) + i sin(3pi/8))
BartSMP [9]
By using <span>De Moivre's theorem:
</span>
If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴ \sqrt[n]{z} =  \sqrt[n]{a} \ (cos \  \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )
k= 0, 1 , 2, ..... , (n-1)


For The given complex number <span>⇒ z = 81(cos(3π/8) + i sin(3π/8))
</span>

Part (A) <span>find the modulus for all of the fourth roots
</span>
<span>∴ The modulus of the given complex number = l z l = 81
</span>
∴ The modulus of the fourth root = \sqrt[4]{z} =  \sqrt[4]{81} = 3

Part (b) find the angle for each of the four roots

The angle of the given complex number = \frac{3 \pi}{8}
There is four roots and the angle between each root = \frac{2 \pi}{4} =  \frac{\pi}{2}
The angle of the first root = \frac{ \frac{3 \pi}{8} }{4} =  \frac{3 \pi}{32}
The angle of the second root = \frac{3\pi}{32} +  \frac{\pi}{2} =  \frac{19\pi}{32}
The angle of the third root = \frac{19\pi}{32} +  \frac{\pi}{2} =  \frac{35\pi}{32}
The angle of the  fourth root = \frac{35\pi}{32} +  \frac{\pi}{2} =  \frac{51\pi}{32}

Part (C): find all of the fourth roots of this

The first root = z_{1} = 3 ( cos \  \frac{3\pi}{32} + i \ sin \ \frac{3\pi}{32})
The second root = z_{2} = 3 ( cos \  \frac{19\pi}{32} + i \ sin \ \frac{19\pi}{32})

The third root = z_{3} = 3 ( cos \  \frac{35\pi}{32} + i \ sin \ \frac{35\pi}{32})
The fourth root = z_{4} = 3 ( cos \  \frac{51\pi}{32} + i \ sin \ \frac{51\pi}{32})
7 0
3 years ago
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