A weather station on the top of a mountain reports that the temperature is currently 0 ∘ C and has been falling at a constant ra
1 answer:
Answer:
After 2 hours: -6°C.
After 5 hours: -15°C.
After hours: -1.5°C
1 hour ago: 3°C.
3 hours ago: 9°C.
4.5 hours ago: 13.5°C.
To find these values, you simply need to multiply the hours elapsed by 3°C. Subtract from 0°C for future temperatures, and ADD to 0°C for the past.
Let's say you are solving for the temperature in 5 hours. All you need to do is:
3°C× 5= 15°C. 0°C-15°C= -15°C
For the temperature 3 hours AGO, what you will need to do instead is:
3°C×3= 9°C. 0°C+ 9°C= 9°C.
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Answer:
Image 1
Step-by-step explanation:
To answer this question, we need to know how to use a box plot.
I've attached an image that demonstrates this well and can teach you what each part of the box plot means.
Specifically, the 2 farthest dots at the end are the minimum and maximum. The two sides where the box starts are the lower and upper quartiles. Finally, the line in the middle of the box is the median.
With this, we can analyze each box plot and determine which one is correct.
<em><u>Box Plot 1: </u></em><em>Everything is plotted correctly- Maximum and minimum plotted correctly, median plotted correctly, upper and lower quartile plotted correctly.</em>
<u>Box Plot 2:</u> Everything plotted correctly EXCEPT maximum of 48 is represented at 46.
<u>Box Plot 3:</u> Everything plotted correctly EXCEPT the upper quartile of 45 is at 39.
<u>Box Plot 4:</u> Upper quartile represented at 39 and maximum represented at 46 are both incorrect.
Answer:
<em>The base is 24 cm long.</em>
Step-by-step explanation:
<u>Equations</u>
Let's call
b= base of the triangle
h=height of the triangle
The base is 9 cm longer than the height, thus:
b = h + 9
The area of the triangle is:
And its value is 180:
Multiplying by 2:
Operating:
Factoring:
The only valid positive solution is:
h = 15 cm
And b = h + 9 = 24
b = 24 cm
The base is 24 cm long.
Hey!
Hope this Helps...
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Below, I added what the graph of (x^2)-2 looks like...
The answer is A. (0, -2); Minimum
