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RoseWind [281]
2 years ago
10

You randomly choose a shape from the set of unshaded shapes, then you randomly choose a shape from the set of shaded shapes as s

hown. What is the probability of choosing an unshaded cube followed by a shaded cube?

Mathematics
1 answer:
aliina [53]2 years ago
6 0

The probability of choosing an unshaded cube followed by a shaded cube is 2/9

<h3>How to determine the probability?</h3>

The sample space is given as:

Unshaded shapes = 10

Shaded shapes = 9

There are 5 unshaded cubes and 4 shaded cubes.

So, the required probability is:

P = 5/10 * 4/9

Evaluate the product

P = 2/9

Hence, the probability of choosing an unshaded cube followed by a shaded cube is 2/9

Read more about probability at:

brainly.com/question/251701

#SPJ1

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goblinko [34]

Answer:

Amount=15,000(1+1.75%)^3

Step-by-step explanation:

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4 years ago
16% of 130 is what number
earnstyle [38]
130 • .16 = 20.8 or 20 (4/5) or 104/5
Put the answer as 20.8 unless specified otherwise.
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4 years ago
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Larry has 4-cent stamps and 9-cent stamps, which he can combine to produce various amounts of postage. For example, he can make
Tju [1.3M]

Answer:

  • the largest number that cannot be made is 23
  • see below for an explanation

Step-by-step explanation:

<em>Why numbers greater than 23 can be made</em>

From any number that Larry can make that includes an appropriate number of stamps, Larry can ...

  • add 1 by adding 1×9 and taking away 2×4
  • add 2 by adding 2×9 and taking away 4×4
  • add 3 by adding 3×9 and taking away 6×4
  • add 4 by adding 1×4
  • add 5 by adding 4 and 1 (add 9, take away 4)
  • add 6 by adding 4 and 2 (add 2×9, take away 3×4)
  • add 7 by adding 4 and 3 (add 3×9, take away 5×4)
  • add 8 by adding 2×4
  • add 9 by adding 1×9

Clearly, for Larry to be able to continue adding any number, he must start with a number that contains at least 6×4 cents = 24 cents.

Larry can make 24 cents from 6 4-cent stamps. Using the above table, he can add any amount to that.

___

<em>Why 23 cannot be made</em>

For 23 cents, the number of stamps must include 0, 1, or 2 9-cent stamps, so there are 3 cases to try for making 23:

  • 23 cannot be made from 0 9-cent stamps because 23 is not divisible by 4
  • 23 cannot be made using 1 9-cent stamp, because 14 is not divisible by 4
  • 23 cannot be made using 2 9-cent stamps, because 5 is not divisible by 4.

Therefore, 23 cannot be made.

7 0
4 years ago
Rearrange the formula to make t the subject:<br> S=d/t
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Answer:

t = d/S

Step-by-step explanation:

S = d/t

Cross multiply

S x t = d

Divide both sides by S

S/S x t = d/S

t = d/S

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Quadrilaterals DONT and WALK are similar. Find the length of side DO.
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Answer is B 9
X/3=15/5
45/5
x=9
So answer B
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3 years ago
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