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Romashka [77]
3 years ago
13

PLS HELP ME ASAP WITH 37 (SHOW WORK + CORRECT ANSWER ONLY) * LOTS OF POINTS!

Mathematics
2 answers:
MrRa [10]3 years ago
7 0
B 
42 times 25.5=1071
771.1/1071= 0.72
(rounded)
not sure
just olya [345]3 years ago
4 0
First, we need to find the area of the wall.  We do this by multiplying the length times the width.  This is equal to 42*25.5=1070 square feet.  Now, we divide the cost by the area to find our answer.  This is equal to 

771.12/1070=$0.72 dollars per square foot, or answer B.
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Someone please help I’ve been spamming on this and no one has helped yet so please
Gre4nikov [31]

Answer:

The value of x would 12.2.

Step-by-step explanation:

You have to use the pythagorean theorem to solve this.

a = 5.85 (11.7/2)

b = what we are trying to find

c = 13.5

\sqrt{13.5^{2} - 5.85^{2}  } = 12.1666 which rounds to 12.2

I hope this helps, I apologize if it isn't right.

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3 years ago
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Answer:

-3, -2, -1, 0, 1, 2, 3

Step-by-step explanation:

6 0
3 years ago
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Add and Subtract Rational Expressions with a Common Denominator
Sladkaya [172]

Answer:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}

Operating on the numerators:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}

Removing parentheses:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}

Simplifying:

\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}

The expression cannot be further simplified.

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3 years ago
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Answer:

r = 2

Step-by-step explanation:

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r = 2

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