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Nastasia [14]
3 years ago
13

Please help meeeeeeee​

Mathematics
2 answers:
mamaluj [8]3 years ago
7 0

https://youtu.be/QnydfcNVJoQ

sypport my channel pls pls

channel name sabrina clodia

Jet001 [13]3 years ago
3 0

Answer:

x + y = 60

Step-by-step explanation:

2x + 2y + 60 = 180 \\ 2x + 2y  = 180 - 60 \\ 2x + 2y = 120 \\  \frac{2x + 2y}{2}  = \frac{120}{2}  \\ x + y = 60 \\

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Determine which number has a greater magnitude."<br><br> 7 and -8
MariettaO [177]

Answer:

7

Step-by-step explanation:

-8 is a negative number for example if you have -8 and you wanna get it to 0 you add 8 you don't have to do that with 7 it's a "positive" number

3 0
3 years ago
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4k + 12 = 52<br> using algbra
grigory [225]

Answer:

k=10

Step-by-step explanation:

4k + 12= 52

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5 0
3 years ago
Theo and Kade worked on a school project together. Theo worked on the project 3 fewer hours than Kade did. Altogether, they work
kow [346]

Answer:Theo worked for 10.5 hours.

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Step-by-step explanation:

6 0
3 years ago
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Wen is factoring the polynomial, which has four terms. 6x3 – 12x2 7x – 14 6x2 (x – 2) 7(x – 2) Which is the completely factored
bonufazy [111]

The factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).

<h3>What is a factor?</h3>

A factor of n is a number which when multiplied by another number gives us the number n.

In order to factorize the polynomial 6x³ – 12x² + 7x – 14, we need to take the common terms out of the given polynomial, therefore, the polynomial can be factorized as,

6x^3-12x^2+7x - 14 \\\\

Taking the common term 6x² out from the first two terms, and then 7 from the next two terms, therefore, the polynomial can be written as

6x^3-12x^2+7x - 14 \\\\= 6x^2(x-2)+7(x-2)\\\\=(6x^2 +7)(x-2)

Hence, the factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).

Learn more about Factors:

brainly.com/question/6810544

8 0
2 years ago
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Anyone would like to do this im so bad at math lm(a)o you will get brainliest if you do this correctly
Maru [420]

Answer:

1.548

Step-by-step explanation:

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