Ask question

Ask question

All categories

2 years ago

12

If it takes 2/3 hours to paint 2/5 room how many hours does it take to paint one room

1 answer:

Mandarinka [93]2 years ago

4 0

Step-by-step explanation:

2/3 hours for 2/5 room.

that means

5×2/3 = 10/3 hours for 5×2/5 = 2 rooms

and then 1 room in 10/3 / 2 = 5/3 hours

You might be interested in

2.5 x 10 to the third power times what number is equal to 5 x 10 to the sixth power?

Taya2010 [7]

Answer:

2 is the number because half of 5 is 2.5

4 0

3 years ago

What is 1.3+(-2.4)<br> enter your answer, as a decimal.

4vir4ik [10]

-1.1 should be the right answer

6 0

3 years ago

Read 2 more answers

How is human impact on the tundra and the rainforests similar? a. Both have been impacted by oil drilling and mining. b. Both ha

andrew11 [14]

Answer: This is a guess I am not that smart

c. Both have been impacted by overgrazing and radioactive pollution.

7 0

3 years ago

Read 2 more answers

You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then

gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is $d\theta_1 =(14.36p)^o$

Step-by-step explanation:

From the question we are told that

The angle of elevation is $\theta_1 = 15 ^o = \frac{\pi}{12}$

The height of the tree is h

The distance from the base is D

h is mathematically represented as

$h = D tan \theta$ Note : this evaluated using SOHCAHTOA i,e

$tan\theta = \frac{h}{D}$

Generally for small angles the series approximation of $tan \theta \ is$

$tan \theta = \theta + \frac{\theta ^3 }{3}$

So given that $\theta = 15 \ which \ is \ small$

$h = D (\theta + \frac{\theta^3}{3} )$

$dh = D (1 + \theta^2) d\theta$

=> $\frac{dh}{h} = \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta$

Now from the question the relative error of height should be at most

$\pm p$ %

=> $\frac{dh}{h} = \pm p$

=> $\frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta = \pm p$

=> $d\theta = \pm \frac{\theta + \frac{\theta^3}{3} }{1+ \theta ^2} * \ p$

So for $\theta_1$

$d\theta_1 = \pm \frac{\theta_1 + \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} * \ p$

substituting values

$d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p$

=> $d\theta_1 = 0.25 p$

Converting to degree

$d\theta_1 = (0.25* 57.29) p$

$d\theta_1 =(14.36p)^o$

4 0

3 years ago

Find the measure of the arc

steposvetlana [31]

The answer is kindly 21 (100% correct)

3 0

3 years ago