4. When reading the stem and leaf plot the only values that fall between the range of 40 < x <60 is the 4 values of 45. They are located at the tail end of the 4 stem after the zeros. The 40s and 60s are not counted because it is not mentioned equal to 40 or 60.
Answer:
Height of the silo = 18 feet.
Step-by-step explanation:
From the figure attached BC is the length of the silo and the height of the farmer is 5 ft.
Farmer is standing at 8 ft distance from the silo.
From triangle AEC,
tan(∠CAE) = 
= 
m(∠CAE) = 
= 32°
m∠BAE = 90° - 32° = 58°
From the triangle ABE,
tan58° = 
BE = 8tan58°
BE = 12.8 ft
Total height of the silo = BE + EC
= 12.8 + 5
= 17.8
≈ 18 ft
Therefore, total height of the silo is 18 ft.
Answer:
The radius of hole is 5 feet
Step-by-step explanation:
Depth of conical hole = 9 feet
Let the radius of hole be r
Volume of conical hole =
So, Volume of conical hole =
We are given that volume of a CONE-shaped hole is 75pi ft cubed.
So,



r=5
Hence The radius of hole is 5 feet
<span>Volume of the Sphere V = 4/3pi x r^3
So when diameter d = 3 inches => r = 1.5 inches
volume of the sphere = 4.188 x r^3 = 4.188 x 1.5^3 = 14.14 in
So when diameter d = 8 inches => r = 4 inches
volume of the sphere = 4.188 x r^3 = 4.188 x 4^3 = 268.03 in
So when diameter d = 9 inches => r = 4.5 inches
volume of the sphere = 4.188 x r^3 = 4.188 x 4.5^3 = 381.63 in
value for option (a) is 3 x 14.14 = 42.42 inches
value for option (b) is 268.03 inches
value for option (c) is 381.63 / 2 = 190.815 inches
So the correct option would be (b)</span>
The letter A represents the smallest value in the data collection, which would be 17