2 years ago

Y=8x+7 and -8x+y=7 solve algebretically

Mathematics

1 answer:

Nadusha1986 [10]2 years ago

6 0

Answer:

infinitely many solution

Step-by-step explanation:

-8x + 8x + 7 = 7

7 = 7

You might be interested in

If f(x) = 3x – 2 and g(x) = 2x + 1, find (f + g)(x). please help :C

Luba_88 [7]

(f+g)(x) = f(x) + g(x)

(f+g)(x) = 3x-2 + 2x+1

(f+g)(x) = (3x+2x) + (-2+1)

(f+g)(x) = 5x - 1

3 0

4 years ago

Read 2 more answers

How do you do 1/8 the sum of 23 and 17

Mariulka [41]

$\sf 23+17=40 \\ \\ \frac{1}{8}*40= \frac{40}{8}=\boxed{\sf 5}$

6 0

4 years ago

Read 2 more answers

Delvig [45]

Answer:

y= 1/2 x +7

the slope is 1/2 since hwne it's perpendicular, it's reciprocal and the sign also changes

Step-by-step explanation:

3= -4 +b

b= 7

4 0

3 years ago

Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon

Lisa [10]

Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

$h(t)=-16t^2+40t+5$

we know that

When the ball hits the ground, the height is equal to zero

$-16t^2+40t+5=0$

The formula to solve a quadratic equation of the form

$at^{2} +bt+c=0$

is equal to

$t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+40t+5=0$

$a=-16\\b=40\\c=5$

substitute in the formula

$t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}$

$t=\frac{-40\pm\sqrt{1,920}} {-32}$

$t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec$

$t=\frac{-40-\sqrt{1,920}} {-32}=2.62\ sec$

therefore

The solution is t=2.62 seconds

4 0

3 years ago

When Gabby went food shopping, she spent $14.90 on 5 bags of marshmallows to make Rice Krispie treats. She has to go to the stor

dusya [7]

the answer is $20.70

3 0

3 years ago