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Evgen [1.6K]
2 years ago
15

Please help me with this

Mathematics
1 answer:
Galina-37 [17]2 years ago
3 0
1 1/8 square feet

1 4/5 • 1 5/8 = 9/8
9/8 reduces to 1 1/8

I hope this helps you :)
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Compare 6.23x10^14 and 8.912x10^12
Tju [1.3M]

Answer:

hello : 6.23x10^14 >  8.912x10^12^12

Step-by-step explanation:

let : A= 6.23x10^14 and  B =  8.912x10^12

A= (6.23x10^2) x10^12  ... because : 10^14 = 10^2x10^12

A = 623 x 10^12

623 > 8.912

so : A > B

3 0
3 years ago
The area model shows 3 1/4 what is 3 Times 3 1/4
Aneli [31]

Answer:

Concept: Basic Multiplication

  1. You have 3 1/4 which can be said in decimal form to be 3.25
  2. You multiply it by 3 to get 9.75 or 9 3/4
  3. Hence D
  4. Rate brainlist
8 0
2 years ago
Which expression shows the correct multiplication of the following polynomilas? 3x(6x^2-3x+7)
snow_tiger [21]

Answer: 18x^3-9x^2+21x

Solution:

3x(6x^2-3x+7)=

Applying the distributive property in the multiplication to eliminate the parentheses:

(3x)(6x^2)+(3x)(-3x)+(3x)(7)=

(3*6)x^(1+2)+3*(-3)x^(1+1)+(3*7)x=

18x^3-9x^2+21x

8 0
3 years ago
The length of a rectangle is 12 in. and the perimeter is 56 in. find the width of the rectangle
pentagon [3]
The perimeter p of the rectangle with length l and width w is:
p = 2l + 2w
that is, two times its length and two times its width, lets solve for the width w and substitute known data:
<span>p = 2l + 2w
</span>2w = p - 2l
w = (<span>p - 2l</span>)/2
w = (56 - (2*12))/2
w = (56 - 24)/2
w = 32/2
w = 16
therefore the width of the rectangle is 16 in
8 0
3 years ago
What is the easiest way to solve a quadratic equation?​
algol [13]

Answer: This is an opinion, look below! :)

Step-by-step explanation:

Factor the expression. To factor the expression, you have to use the factors of the {\displaystyle x^{2}}x^{2} term (3), and the factors of the constant term (-4), to make them multiply and then add up to the middle term, (-11). Here's how you do it:

Since {\displaystyle 3x^{2}}3x^{2} only has one set of possible factors, {\displaystyle 3x}3x and {\displaystyle x}x, you can write those in the parenthesis: {\displaystyle (3x\pm ?)(x\pm ?)=0}(3x\pm ?)(x\pm ?)=0.

Then, use process of elimination to plug in the factors of 4 to find a combination that produces -11x when multiplied. You can either use a combination of 4 and 1, or 2 and 2, since both of those numbers multiply to get 4. Just remember that one of the terms should be negative, since the term is -4.[3]

By trial and error, try out this combination of factors {\displaystyle (3x+1)(x-4)}(3x+1)(x-4). When you multiply them out, you get {\displaystyle 3x^{2}-12x+x-4}3x^{2}-12x+x-4. If you combine the terms {\displaystyle -12x}-12x and {\displaystyle x}x, you get {\displaystyle -11x}-11x, which is the middle term you were aiming for. You have just factored the quadratic equation.

As an example of trial and error, let's try checking a factoring combination for {\displaystyle 3x^{2}-11x-4=0}3x^{2}-11x-4=0 that is an error (does not work): {\displaystyle (3x-2)(x+2)}(3x-2)(x+2) = {\displaystyle 3x^{2}+6x-2x-4}3x^{2}+6x-2x-4. If you combine those terms, you get {\displaystyle 3x^{2}-4x-4}3x^{2}-4x-4. Though the factors -2 and 2 do multiply to make -4, the middle term does not work, because you needed to get {\displaystyle -11x}-11x, not {\displaystyle -4x}-4x.

7 0
2 years ago
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