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2 years ago

Me podrían ayudar con esto?

Mathematics

1 answer:

xxTIMURxx [149]2 years ago

7 0

Answer:

Step-by-step explanation:

This would be basically be zero/0 because anything times 0 is just nothing.

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Write the expression in factored form s^2-20s-100

KatRina [158]

Answer:

The factors of given expression are 10+10√2 and 10-10√2.

Step-by-step explanation:

We have given a quadratic expression.

s²-20s-100

We have to find factors of given expression.

We use quadratic formula to find factors.

x = (-b±√b²-4ac) / 2a

From given expression, a = 1 , b = -20 and c = -100

Putting values in above formula, we have

x = (-(-20)±√(-20)²-4(1)(-100) ) / 2(1)

x = (20±√400+400 ) / 2

x = (20±√800) / 2

x = (20± √400×2) / 2

x = (20±20√2) / 2

x = 10±10√2

Hence, the factors of given expression are 10+10√2 and 10-10√2.

3 0

3 years ago

What is 5 divided by 1/4

velikii [3]

The answer is 20.

Hope this helps!! May I have brainliest?

4 0

3 years ago

Read 2 more answers

dimensions of a house are 300 feet by 125 feet . if 1 inch represent 50 feet what are the dimensions of the house on the drawing

Leya [2.2K]

The house would be -1,304 inches

4 0

3 years ago

A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms. What's its density in grams per cubic centimete

Ahat [919]

Answer:

The density of the bar of gold is 19.32 grams per cubic centimeter .

Step-by-step explanation:

Formula

$Density = \frac{Mass}{Volume}$

As given

A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms.

As 1 kilogram = 1000 gram

Than convert 13.949 kilograms into grams.

13.949 kilograms = 13.949 × 1000 grams

= 13949 grams

Mass = 13949 grams

Volume = 722 cubic centimeter

As put in the formula

$Density = \frac{13949}{722}$

Density = 19.32 grams per cubic centimeter (Approx)

Therefore the density of the bar of gold is 19.32 grams per cubic centimeter .

8 0

3 years ago

What is 104.35 x 34?

Luden [163]

Answer:

3547.90

Step-by-step explanation:

3 0

3 years ago

Me podrían ayudar con esto?​

Me podrían ayudar con esto?