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Helen [10]
3 years ago
14

SHOW YOUR WORK!! :)

Mathematics
2 answers:
saveliy_v [14]3 years ago
4 0
Problem 1.
1 day = 24 hours
58 days = 24 * 58 = 1392 hours
60 minutes = 1 hour
30 minutes = 30/60 hour = 1/2 hour
It takes Keurig a total amount of time of 1392 + 15 + 1/2 = 1407 * 1/2

Problem 2.
Part A: 1 foot = 12 inches 0.5 feet * 12 inches = 6 inches per day
Part B: 1 day = 24 hours 6 inches/24 hours = 0.25 inches per hour
Katen [24]3 years ago
4 0
It takes Keurig a total amount of time of 1392 + 15 + 1/2 = 1407 * 1/2
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The two-way table shows the ages of the players on different soccer teams. A 6-column table has 4 rows. The first column has ent
mamaluj [8]

Answer:

The true statement is:  The probability that a randomly selected player on Team C is 10 years old is \frac{5}{16}.

Step-by-step explanation:

According to the table the total number of 10 years old players on Team C is 5 and the total number of all ages players (8, 9 and 10 years old) on Team C is 16, so the probability that a randomly selected player on Team C is 10 years old is 5/16.

4 0
3 years ago
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Eighteen telephones have just been received at an authorized service center. Six of these telephones are cellular, six are cordl
LenaWriter [7]

Answer:

a) 0.0498

b) 0.1489

c) 0.1818

Step-by-step explanation:

Given:

Number of telephones = 6+6+6= 18

6 cellular, 6 cordless, and 6 corded.

a) Probability that all the cordless phones are among the first twelve to be serviced:

12 are selected from 18 telephones, possible number of ways of selection = ¹⁸C₁₂

Then 6 cordless telephones are serviced, the remaining telephones are: 12 - 6 = 6.

The possible ways of selecting thr remaining 6 telephones = ¹²C₆

Probability of servicing all cordless phones among the first twelve:

= (⁶C₆) (⁶C₁₂) / (¹⁸C₁₂)

= \frac{1 * 924}{18564}

= 0.0498

b) Probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced:

Here,

One type must be serviced first

The 6 remaining to be serviced can be a combination of the remaining two types.

Since there a 3 ways to select one type to be serviced, the probability will be:

= 3 [(⁶C₁)(⁶C₅) + (⁶C₂)(⁶C₄) + (⁶C₃)(⁶C₃) + (⁶C₄)(⁶C₂) + (⁶C₅)(⁶C₁)] / ¹⁸C₁₂

= \frac{3 * [(6)(6) + (15)(15) + (20)(20) + (15)(15) + (6)(6)]}{18564}

= \frac{2766}{18564}

= 0.1489

c) probability that two phones of each type are among the first six:

(⁶C₂)³/¹⁸C₆

\frac{3375}{18564}

=0.1818

5 0
4 years ago
Find B<br> Plzz find the right answer and don’t just guess
LenaWriter [7]

Answer:

Step-by-step explanation:

using pythagoras theorem

a^2 + b^2 = c^2

B^2 + 8^2 = 15^2

B^2 + 64 + 225

B^2 = 225 - 64

B^2 = 161

B = \sqrt{161}    OR  12.7

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3 years ago
Find the nth term of this sequence 5 10 15 20 25 ...
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The NTH term is 5n..
6 0
3 years ago
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Help please! Identify an equation in point slope form for the line perpendicular to Y =-4x + 8 that passes through (-2, 7)
777dan777 [17]

Answer:

D. y-7=\frac{1}{4}(x+2)

Step-by-step explanation:

The point-slope form of a line is given by:

y-y_1=m(x-x_1)

The line given to us has equation; y=-4x+8.

The slope of this line is -4. The of the line perpendicular to this line is the negative reciprocal of the slope of the given line.

Our slope of interest is therefore; m=\frac{1}{4}

Since the point goes through (-2,7), we have x_1=-2,y_1=7.

We plug in the slope and the point into the point-slope formula to obain;

y-7=\frac{1}{4}(x--2)

The required equation is:

y-7=\frac{1}{4}(x+2)

3 0
3 years ago
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