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mariarad [96]
2 years ago
14

Kami is in charge of creating a five-digit code to lock and unlock a secure chamber. She can use any digit from 0 through 9, and

she can use each digit as many times as she wants. She knows she wants to start the code with an even number.
How many possible codes that start with an even number could Kami create?


40,000 codes

50,000 codes

400,000 codes

500,000 codes
Mathematics
2 answers:
Alik [6]2 years ago
7 0

Answer:

50,000 codes

Step-by-step explanation:

took the test

Fynjy0 [20]2 years ago
3 0

We will see that there are 50,000 different possible codes that start with an even number.

<h3>How many possible codes are there?</h3>

We know that the code has 5 digits, each one with 10 possible options (except the first one, when we only can use even digits, so there we have 5 options).

And the numbers can be repeated any number of times through the code, then the total number of different codes that can be made is equal to the product between the numbers of options for each of the digits, we will have:

C = 5*10*10*10*10 = 50,000

So there are 50,000 different codes.

If you want to know more about combinations:

brainly.com/question/251701

#SPJ1

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