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2 years ago

Help please I’m struggling

Mathematics

2 answers:

Lapatulllka [165]2 years ago

5 0

Answer:

28 more kids chose Art than Computer Lab.

Step-by-step explanation:

34 kids chose art. kids schose computer lab.

Take6 from 34 to find out how many kid chose Art than Computer Lab

34 - 6 = 28

28 more kids chose Art than Computer Lab.

lina2011 [118]2 years ago

4 0

34-6=28
The correct answer is 28

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Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

2 years ago

Solve for x(need help)

bija089 [108]

Answer:

x = 18

Step-by-step explanation:

I the given triangle, it appears that M and N are the midpoints of the segments BG and BD respectively. If it so, then let us solve it.

By mid segment theorem:

2MN = GD

2(6x - 51) = 114

12x - 102 = 114

12x = 114 + 102

12x = 216

x = 216/12

x = 18

4 0

2 years ago

Formulas A=bh/2 A=bh and I have 6in 4in 6in 10in and I have to find the area

Naddik [55]

Answer:

Lots of "ifs" here.

A=bh/2 is the formula for the area of a triangle.

A=bh is the formula for the area of a rectangle or a parallelogram.

If the 6 & 4 area the base & height of a rectangle, then (6)(4) = 24 in^2

If the 6 & 10 are the base and height of a triangle, then 1/2(6)(10) = 30 in^2

Step-by-step explanation:

6 0

3 years ago

What is the geometric mean og 6 and 13

lara31 [8.8K]

Answer:

The answer is

Step-by-step explanation:

6 0

2 years ago

a small plane lands at a point 324 miles east and 92 miles north of the point at which it took off. Find the distance the plane

Setler79 [48]

Answer: 336.80 miles, $15.85^{\circ}$ North of east

Step-by-step explanation:

Given

Plane lands at a point 324 miles east and 92 miles north

Distance is given by using Pythagoras theorem

$\Rightarrow d=\sqrt{324^2+92^2}\\\\\Rightarrow d=\sqrt{113,440}\\\\\Rightarrow d=336.80\ \text{miles}$

Direction is given by using figure i.e.

$\Rightarrow \tan \theta=\dfrac{92}{324}\\\\\Rightarrow \tan \theta=0.2839\\\\\Rightarrow \theta=15.85^{\circ}$

Direction is $15.85^{\circ}$ North of east

7 0

2 years ago