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3 years ago

Two angles are vertical. One angle is by degrees and the other angle

Mathematics

2 answers:

Liono4ka [1.6K]3 years ago

7 0

Answer:

Supplementary angles are two angles whose measures add up to 180 degrees. ... Supplementary angles are two angles whose measures add up to 180° . The two angles of a linear pair , like ∠1 and ∠2 in the figure below, are ... If the measure of the angle is twice the measure of the other, find the measure of each angle.

Step-by-step explanation:

icang [17]3 years ago

7 0

Answer: So in this problem the first one is by what degrees? Thanks and will try to help when info is given. I think 72

Step-by-step explanation:

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Write the number with the same value as 28 tens

Tanya [424]

2 onea and 8 tens is a way to express it

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3 years ago

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3(x-6)^4+11=15 solve for x

Tamiku [17]

Answer:

x = 7.07 or 4.925

Step-by-step explanation:

3(x-6)^4+11=15

3(x-6)^4=15-11

(x-6)^4=4/3

x-6 = + $\sqrt[4]{4/3}$ or - $\sqrt[4]{4/3}$

x= + $\sqrt[4]{4/3}$ +6 or - $\sqrt[4]{4/3}$ +6

x = 7.07 or 4.925

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2 years ago

2. What was the purpose of the Civil Defense system?

galina1969 [7]

Answer: civil protection is an effort to protect the citizens of a state (generally non-combatants) from military attacks and natural disasters. It uses the principles of emergency operations: prevention, mitigation, preparation, response, or emergency evacuation and recovery.

Step-by-step explanation:

8 0

3 years ago

Calculus Problem

Roman55 [17]

The two parabolas intersect for

$8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2$

and so the base of each solid is the set

$B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}$

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, $|x^2-(8-x^2)| = 2|x^2-4|$ . But since -2 ≤ x ≤ 2, this reduces to $2(x^2-4)$ .

a. Square cross sections will contribute a volume of

$\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x$

where ∆x is the thickness of the section. Then the volume would be

$\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}$

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

$\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x$

We end up with the same integral as before except for the leading constant:

$\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx$

Using the result of part (a), the volume is

$\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}$

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

$\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x$

and using the result of part (a) again, the volume is

$\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}$

7 0

2 years ago

Look at the photo pick A B C D either one explanation not needed thank you! <3

hjlf

Answer:

Step-by-step explanation:

It's A

5 0

3 years ago

Read 2 more answers