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egoroff_w [7]
2 years ago
13

A marble is selected at random from a jar containing 4 red marbles, 5 yellow marbles, and 3 green marbles. What is the probabili

ty that the marble that gets selected is red?
Mathematics
1 answer:
SSSSS [86.1K]2 years ago
3 0

Answer:

p(picking red)= 4/12 (4 over 12) which can get simplified to 1/3 (1 over 3)

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PLEASE HELP ILL MARK YOU BRAINLIEST Given the expression: 6x10 − 96x2 Factor the entire expression completely. Show the steps of
Mandarinka [93]

Answer:

6x¹⁰ - 96x²

6x²(x⁸ - 16)

B) 6x²(x⁸ - 16)

6x²[(x⁴)² - 4²]

6x²[(x⁴ - 4)(x⁴ + 4)]

6x²(x⁴ + 4)[(x²)² - 2²]

6x²(x⁴ + 4)(x² - 2)(x² + 2)

3 0
3 years ago
Read 2 more answers
When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
9+ 13 + 17 + ...+ 457=
Readme [11.4K]

Answer:

418

Step-by-step explanation: 457-17-13-9=418

To double check: 418 + 17 + 13 + 9 = 457

6 0
3 years ago
What is the rate of 70 miles in 2 hours in unit rate
tamaranim1 [39]
You want one of the values in the ratio to be one for a unit rate. First, write out the ratio. It is 70 miles/2 hours. It's better not to include decimal numbers when you write a ratio when you can, so we're going to make the hours the unit rate. To make 2 -> 1 hour, divide both sides of the ratio by 2. 70/2 = 35. 
The unit rate is 35 mi./hr.
Hope that helped you.
5 0
3 years ago
Read 2 more answers
Y&gt;1 and y&gt;x on a graph
zlopas [31]

So,

y>1\wedge y>x

1. Graph each inequality separately.

2. Choose a test point to determine which side of the line needs to be shaded.

3. The solution to the system will be the area where the shadings from each inequality overlap one another (purple area)

As for the system of inequalities we say it's unbounded.

3 0
3 years ago
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