Answer:
minimum of 13 chairs must be sold to reach a target of $6500
and a max of 20 chairs can be solved.
Step-by-step explanation:
Given that:
Price of chair = $150
Price of table = $400
Let the number of chairs be denoted by c and tables by t,
According to given condition:
t + c = 30 ----------- eq1
t(150) + c(400) = 6500 ------ eq2
Given that:
10 tables were sold so:
t = 10
Putting in eq1
c = 20 (max)
As the minimum target is $6500 so from eq2
10(150) + 400c = 6500
400c = 6500 - 1500
400c = 5000
c = 5000/400
c = 12.5
by rounding off
c = 13
So a minimum of 13 chairs must be sold to reach a target of $6500
i hope it will help you!
For this case we have that by definition, the Greatest Common Factor or GCF, is the largest factor that divides two numbers and the remainder is zero.
We find the factors of 46 and 34:
Thus, the GCF of both numbers is 2.
So, the GCF of both expressions is:
Answer:
Hello There!
Well, as you know a number line is a line where you can place numbers with different spaces between them. It can be used to compare them in distance (the further apart they are on the line, the greater the difference between the two numbers)
Hope This Helps You!
Good Luck :)
- Hannah ❤
Answer:
a)
P(X = 0) = 5/10
P(X = 5) = 3/10
P(X = 10) = 2/10
b)
E = 0·5/10 + 5·3/10 + 10·2/10 = 3.5
V = 0^2·5/10 + 5^2·3/10 + 10^2·2/10 - 3.5^2 = 15.25
