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3 years ago

The value of x is: A. 6 B. 5 C. 2 D. 3 E. 4

Mathematics

2 answers:

kolezko [41]3 years ago

5 0

3x + 1 = 2x + 6
subtract 2x from both sides

x + 1 = 6
subtract 1 from both sides

x = 5

The value of x is B. 5.

Galina-37 [17]3 years ago

3 0

Answer:

x = 5.

Step-by-step explanation:

In order to find the value of x you have to set the equations equal to each other. One you do that you use the operation of pemdas to solve the algebraic equation to find x. so first you subtract 2x from 3x which leaves you with 1x aka just x. Then you subtract one from x and 6 to get x alone. subtracting 1 from x equals 5. putting x equal to 5.

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torisob [31]

Answer:

A. Square for Ape.x

Step-by-step explanation:

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2 years ago

Last year, 800 students attended the career fair at west high school. this year,the number of students who attended the career f

Delvig [45]

Answer:

840

Step-by-step explanation:

Last year, 800 students attended the career fair at West High School.

And, this year the number of students who attended the career fair increased by 5%.

We are asked how many students attended the career fair at West High School this year.

Therefore, the number of students attended the career fair at West High School will be $800[1+\frac{5}{100} ] =800 \times 1.05 = 840$ . (Answer)

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2 years ago

Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method

antoniya [11.8K]

Answer:

The estimate is $- 0.0265\le K \le 0.0465$

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is $n_1 = 400$

The number of faulty breaks of method A is $X_1 = 32$

The number of microchips broken in method B is $n_2 = 400$

The number of faulty breaks of method A is $X_2 = 32$

The proportion of the faulty breaks to the total breaks in method A is

$p_1 = \frac{32}{400}$

$p_1 = 0.08$

The proportion of the faulty to the total breaks in method B is

$p_2 = \frac{28}{400}$

$p_2 = 0.07$

For this estimation the standard error is

$SE = \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1- p_2 )}{n_2} } }$

substituting values

$SE = \sqrt{ \frac{0.08 (1 - 0.08)}{400} + \frac{0.07 (1- 0.07 )}{400} } }$

$SE = 0.0186$

The z-values of confidence coefficient of 0.95 from the z-table is

$z_{0.95} = 1.96$

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

substituting values

$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

$K = - 0.0265 \ or \ K = 0.0465$

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

$- 0.0265\le K \le 0.0465$

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Soloha48 [4]

Answer:

Step-by-step explanation:

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