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Sergio039 [100]
3 years ago
15

a student athlete runs 3 1/2 miles in 30 minutes. A professional runner can run 1 1/4 times as far in 30 minutes. How far can th

e professional runner run in 30 minutes?
Mathematics
2 answers:
Elena L [17]3 years ago
7 0
The professional runner can run 2/3 in 30 minutes
tresset_1 [31]3 years ago
3 0
3 1/2 * 1 1/4 =
7/2 * 5/4 =
35/8 = 4 3/8 miles <==
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Use the figure to write and solve an equation for x
Lera25 [3.4K]
The answer is 6 :)))
5 0
4 years ago
The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of
ser-zykov [4K]

Answer:

p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}, for r_{1} = 0

Step-by-step explanation:

The general form of quintic-order polynomial is:

p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f

According to the statement of the problem, the polynomial has the following roots:

p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)

Then, some algebraic handling is done to expand the polynomial:

p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)

p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x

If r_{1} = 0, then:

p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}

5 0
3 years ago
How do i do this question<br> y=-1/2x-2 i am suppoted to graph it
inysia [295]
No your supposed to do the math and cancel out each nunber until you find y
8 0
3 years ago
How to solve this 7/8 n=63
ololo11 [35]

Answer:

It equals n=72

Step-by-step explanation:

7/8 n=63

7/8 n=63

7n/8=63

8. 7n/8=8. 63

7n=504

7n/7=504/7

n=72

7 0
3 years ago
Bethany wrote the equation X+ (x+2)+(+4)= 91 when she was told that the sum of three consecutive odd integers had a
azamat

Answer:

Option A) Bethany is correct because consecutive odd integers will each have a difference of two

Step-by-step explanation:

The sum of 3 consecutive odd integers is 91. Let the first odd integer is x. The next odd integer will be obtained by adding 2 in x i.e. (x + 2). The third odd integer will be obtained by adding 2 in the second odd integer i.e. (x + 2) + 2 = x + 4

So, the 3 odd integers will be:

x  , (x+2) and (x+4)

Their sum is given to be 91. So we can write:

x + (x+2) + (x+4) = 91

Hence, we can conclude that: Bethany is correct because consecutive odd integers will each have a difference of two.

Other options are not correct because consecutive odd integers always increase by 2. For example, the next odd integer after 1 is 3, which is obtained by adding two, similarly the next odd will be 5 and so on.

5 0
4 years ago
Read 2 more answers
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