Plug in 3 for f(x)
f(3)=(3)²+7
f(3)=9+7
f(3)=16
Hoped this helped!
Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³
Answer:
x = 420/11
Step-by-step explanation:
Answer: 818.4
Step-by-step explanation:
Using the area of a sector formula, we get the area of the entire sector is 
.
Using the formula 
, we get the area of the triangle is 
.
So, the area of the shaded sector is 
Middle right is your answer
