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lozanna [386]
2 years ago
13

Could ya'll help me you know I'm bad at it

Mathematics
2 answers:
Tresset [83]2 years ago
8 0
She has 2 outfits Bc there’s only 2 pairs of shoes so therefore only 2 outfits
ehidna [41]2 years ago
4 0

Answer:

Jane has 30 different outfits she can choose from.

Step-by-step explanation:

Jane has 3 pairs of pants, 5 shirts for each pair of pants, and 2 shoes for each shirt. So the total amount of different outfits she can wear is 3 * 5*2 = 30 different outfits.

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Natalie and John are both saving coins in jars for a rainy day. Natalie currently has 1 1!8 jars of coins, and John has 9/14 of
Leokris [45]
Natalie will have 10/14 coins
8 0
3 years ago
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Find M< NML ANSWER -156 78 162 81​
seraphim [82]

Answer:

156

its 156 owo

brainly?

7 0
2 years ago
I have 2 Questions.
aleksandr82 [10.1K]

Answer:

looks hard omgong

5 0
2 years ago
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(Based on Q1 ~ Q3) According to the Bureau of the Census, 18.1% of the U.S. population lives in the Northeast, 21.9% inn the Mid
vekshin1

Answer:

We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.

Step-by-step explanation:

The null Hypothesis: Geographical distribution of hotline callers could be the same as the U.S. population distribution

Alternative hypothesis: Geographical distribution of hotline callers could not be the same as the U.S. population distribution

The populations considered are the Midwest, South, Northeast, and west.

The number of categories, k = 4

Number of recent calls = 200

Let the number of estimated parameters that must be estimated, m = 0

The degree of freedom is given by the formula:

df = k - 1-m

df = 4 -1 - 0 = 3

Let the significance level be, α = 5% = 0.05

For  α = 0.05, and df = 3,

from the chi square distribution table, the critical value = 7.815

<u>Observed and expected frequencies of calls for each of the region:</u>

<u>Northeast</u>

Observed frequency = 39

It contains 18.1% of the US Population

The probability = 0.181

Expected frequency of call = 0.181 * 200 = 36.2

<u>Midwest</u>

Observed frequency = 55

It contains 21.9% of the US Population

The probability = 0.219

Expected frequency of call = 0.219 * 200 =43.8

<u>South</u>

Observed frequency = 60

It contains 36.7% of the US Population

The probability = 0.367

Expected frequency of call = 0.367 * 200 = 73.4

<u>West</u>

Observed frequency = 46

It contains 23.3% of the US Population

The probability = 0.233

Expected frequency of call = 0.233 * 200 = 46

x^{2} = \sum \frac{(O_{i} - E_{i})  ^{2} }{E_{i} } ,   i = 1, 2,.........k

Where O_{i} = observed frequency

E_{i} = Expected frequency

Calculate the test statistic value, x²

x^{2} = \frac{(39 - 36.2)^{2} }{36.2} + \frac{(55 - 43.8)^{2} }{43.8} + \frac{(60 - 73.4)^{2} }{73.4} + \frac{(46 - 46.6)^{2} }{46.6}

x^{2} = 5.535

Since the test statistic value, x²= 5.535 is less than the critical value = 7.815, the null hypothesis will not be rejected, i.e. it will be accepted. We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.  

7 0
2 years ago
HALP ME WITH THIS MATH PLSS
pentagon [3]
The answer is 63/5ft long of the actual car. Hope this helps :)
8 0
3 years ago
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